n = 9, y = 129.5, and s₂ = 5.36. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALT * ) Does the interval suggest that precise information about the value of this difference is available? Because the interval is so wide, it appears that precise information is not available. O Because the interval is so wide, it appears that precise information is available. O Because the interval is so narrow, it appears that precise information is not available. O Because the interval is so narrow, it appears that precise information is available. -17.878 -13.323
n = 9, y = 129.5, and s₂ = 5.36. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALT * ) Does the interval suggest that precise information about the value of this difference is available? Because the interval is so wide, it appears that precise information is not available. O Because the interval is so wide, it appears that precise information is available. O Because the interval is so narrow, it appears that precise information is not available. O Because the interval is so narrow, it appears that precise information is available. -17.878 -13.323
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
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Transcribed Image Text:Suppose μ₁ and ₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 9, x = 113.9, s₁ = 5.02,
n = 9, y = 129.5, and s₂ = 5.36. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your
answers to two decimal places.)
USE SALT
-17.878
x )
Does the interval suggest that precise information about the value of this difference is available?
● Because the interval is so wide, it appears that precise information is not available.
O Because the interval is so wide, it appears that precise information is available.
O Because the interval is so narrow, it appears that precise information is not available.
O Because the interval is so narrow, it appears that precise information is available.
x -13.323
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