N2 delta Hf=0 , H2 delta Hf= -286 kj , -80.8 kj 4. C delta Hf =0 1/2O2 delta Hf= 219.2kj, CO delta Hf= -110.5kj Give me answer of 3 and 4 5. Calculate the change in enthalpy for the following reactions:CHao) ++ Oxo) CO29) + H,01.CaHszo) + Or0) CO20) + H,O2.3. Na) + HzaHaceNH)COm4.

3) The given reaction is: N2(g)+3H2(g)→2NH3(g) Calculation of ∆H˚f:…

Answered: N + H) CO 209) 4. G 3.

Science

Chemistry

N + H) CO 209) 4. G 3.

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter12: Thermodynamic Processes And Thermochemistry

Section: Chapter Questions

Problem 51P

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Concept explainers

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.

Question

N2 delta Hf=0 , H2 delta Hf= -286 kj , -80.8 kj

4. C delta Hf =0 1/2O2 delta Hf= 219.2kj, CO delta Hf= -110.5kj

Give me answer of 3 and 4

5. Calculate the change in enthalpy for the following reactions:
CHao) +
+ Oxo) CO29) + H,0
1.
CaHszo) + Or0) CO20) + H,O
2.
3. Na) + Hza
Hace
NH)
COm
4.

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