n mice, albinism (g) is recessive to grey coat colour (G). A grey mouse mated with an albino mouse. Over the course of several months, 38 pups were born. Out of 38 pups, 17 had a grey coat, and 21 were albino. Which of the following rows correctly identifies the parental and F1 generation genotypes?
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In mice, albinism (g) is recessive to grey coat colour (G). A grey mouse mated with an albino mouse. Over the course of several months, 38 pups were born. Out of 38 pups, 17 had a grey coat, and 21 were albino.
Which of the following rows correctly identifies the parental and F1 generation genotypes?
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- In guinea pigs, black hair color (B) is dominant and brown hair color (b) is recessive. Long hair (L) is dominant and short hair (l) is recessive. Answer the following questions: a) Diagram the complete cross: BBLL x bbll b) What are the genotypes and phenotypes of the F1 generation?Use the following information to answer the next four questions. Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Part A: Record the phenotypes and the phenotype ratio in lowest terms. Part B: Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these…Use the following information to answer the next four questions. Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Part A: Record the phenotypes and the phenotype ratio in lowest terms. Part B: Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these…
- Use the following information to answer the next question.In a testcross, the parent that is homozygous recessive for the genes being studied is called the testcross parent. The parent that has the dominant phenotype of the genes being studied is called the non-testcross parent.Which of the following is NOT a reason that a testcross is a useful technique when studying the inheritance of a trait a. The relative frequencies of the different phenotypes among the testcross progeny can be used to map linked genes. b. The gametes produced by the testcross parent are determined from the testcross progeny. c. A testcross can determine if an individual with the dominant phenotype is homozygous or heterozygous. d. Because the testcross parent can contribute only recessive alleles, the alleles contributed by the other parent will be expressed in the offspring of the testcross.Imagine a cross between a man and a woman having the following genotypes: Genotype of the Husband Genotype of the Wife Aa bb Dd Gg Hh RR Tt X Aa Bb Dd gg Hh Rr Tt Suppose, that the A allele exhibited incomplete dominance over the a allele and the T allele exhibited incomplete dominance over the t allele. In that instance, how many different phenotypes would be possible among the offspring of this same couple?In guinea pigs, black hair colour (B) is dominant and brown hair colour (b) is recessive. Long hair (L) is dominant and short hair (l) is recessive. Answer the following questions: (a) Find the gamete types for the cross: BbLl X BbLL (b) What are the phenotypes of the parent generation? (c) What are the genotypes and phenotypes of the F1 generation?
- Using the following information perform following crosses using the forked line and predict all possible phenotypes types of the offspring. List the number and description of the phenotypes of the offspring. 1. aa BB Cc Dd Ee X aa bb Cc Dd EE 2. Ff Rr Gg dd Bb X Ff RR Gg Dd Bb 3. Dd gg JJ bb Hh Ee X DD GG Jj Bb Hh EeIf a man with dark skin whose genotype is AaBB reproduces with a woman who has light skin (aaBb), what are the possible skin colors that their children will have? Develop a Punnett square and list the possible genotypes & phenotypes. For your convenience, a table is presented below that shows several possible genotypes & phenotypes: Genotypes Phenotypes AABB Very dark skin AABb or AaBB Dark skin AaBb, AAbb, or aaBB Medium brown skin Aabb or aaBb Light skin aabb Very light skinIn a species of dog, a mutant gene that causes deafness is found on the Y chromosome. What type of offspring will be produced between a cross of male dog whose father is deaf, and female dog whose father is not deaf? Question 16 options: 25% normal female dogs, 25 % deaf female dogs, 25 % normal male dogs, 25 % deaf male dogs 50% normal female dogs, 50 % deaf male dogs 50% deaf female dogs, 50 % deaf male dogs 50% normal female dogs, 25 % deaf male dogs, 25% normal male dogs
- You cross two wildtype (short-tailed) chipmunks, and collect a male offspring with a particularly long tail, which you name Dale. Tail length is controlled by the gene T, which is a maternally imprinted gene in chipmunks. Choose the best answers to complete the following statements. choose the correct answer option for each Dale’s allele for a long tail was inherited from the female/male/ unknown parent. That parent did not express the long tail phenotype because the allele was inherited from the parent’s own mother/father/unknown parent . If one of Dale’s offspring inherits the long tail allele from him, it will not /will/either will or will not express that phenotype.Given the pedigree below, answer the following questions. Note that filled symbols represent affected individuals. You assume that the allele carrying the disease is rare and therefore individuals marrying into the family are unlikely to have defective alleles. Also, assume complete penetrance. Q2) What are the genotypes of the following individuals listed in the table below? Use the uppercase “A” to represent the dominant allele and lowercase “a” for the recessive allele. Individual Genotype II-7 III-5 IV-1 IV-3 I-2 III-7Use the following parents to create a Punnet Square and answer the question. Cross a heterozygous father with a homozygous recessive mother. (you can use the letter A for your parental genotypes) What percent of the offspring will be homozygous recessive?