Na3AlF6 is synthesized according to the following reaction. Al2O3 (k) + 6 NaOH (aq) + 12HF (g) à 2 Na3AlF6 (k) + 9 H2O (s) In an experiment; 6.55 g Al2O3 and excess HF were dissolved in 1.75 L of 0.15 M NaOH . If 20 g Na3AlF6 were obtained at the end of the experiment, What is the limiting reagent? What is the real yield? What is the theoretical yield? What is % yield (percentage yield
Na3AlF6 is synthesized according to the following reaction. Al2O3 (k) + 6 NaOH (aq) + 12HF (g) à 2 Na3AlF6 (k) + 9 H2O (s) In an experiment; 6.55 g Al2O3 and excess HF were dissolved in 1.75 L of 0.15 M NaOH . If 20 g Na3AlF6 were obtained at the end of the experiment, What is the limiting reagent? What is the real yield? What is the theoretical yield? What is % yield (percentage yield
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter13: Solutions And Their Behavior
Section: Chapter Questions
Problem 97SCQ
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Na3AlF6 is synthesized according to the following reaction.
Al2O3 (k) + 6 NaOH (aq) + 12HF (g) à 2 Na3AlF6 (k) + 9 H2O (s)
In an experiment; 6.55 g Al2O3 and excess HF were dissolved in 1.75 L of 0.15 M NaOH . If 20 g Na3AlF6 were obtained at the end of the experiment,
- What is the limiting reagent?
- What is the real yield?
- What is the theoretical yield?
- What is % yield (percentage yield)?
(MA (Na3AlF6): 209.94 g/mol; (Al2O3): 101.96 g/mol; (NaOH): 39.997 g/mol)
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