NaHCO, can be used to neutralize excess acid in situations such as, for instance, acid spills in the laboratory. The reaction is: H'(ag) = HCO3 (aq) H2O(1) + CO2(g). How many grams of NaHCO3 would be required to neutralize the acid in 75.5 mL of 1.00 M nitric acid? O 6.34 grams O 75.5 grams O 0.899 grams O 1.11 grams O 7.55 grams eTextbook and Media Attempts: 0 of 2 used Submit Answer Save for Later

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 62QAP: Ten mL of concentrated H3PO4 (91.7% by mass, d=1.69g/mL) was accidentally poured into a beaker...
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NaHCO3 can be used to neutralize excess acid in situations such as, for instance, acid spills in the laboratory. The reaction is: H*(ag) +
HCO3 (aq) → H20(1) + CO2(g). How many grams of NaHCO3 would be required to neutralize the acid in 75.5 mL of 1.00 M nitric acid?
O 6.34 grams
O 75.5 grams
O 0.899 grams
O 1.11 grams
O 7.55 grams
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Transcribed Image Text:View Policies Current Attempt in Progress NaHCO3 can be used to neutralize excess acid in situations such as, for instance, acid spills in the laboratory. The reaction is: H*(ag) + HCO3 (aq) → H20(1) + CO2(g). How many grams of NaHCO3 would be required to neutralize the acid in 75.5 mL of 1.00 M nitric acid? O 6.34 grams O 75.5 grams O 0.899 grams O 1.11 grams O 7.55 grams eTextbook and Media Save for Later Attempts: 0 of 2 used Submit Answer pe here to search 18 Cip insert IOI 林 24 7 8 Y D G K pau M ctr alt
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