Nana AB. supplies a range of computer hardware and software to 2000 schools within a large municipal region of Spain. When Nana AB. won the contract the issue of customer service was considered to be central to the company being successful at the final bidding stage. The company has now requested that its customer service director creates a series of graphical representations of the data to illustrate customer satisfaction with the service. The following data has been collected during the last six months and measures the time to respond to the received complaint (days). 5 24 34 6 61 56 38 32 87 78 34 9 67 4 54 23 56 32 86 12 81 32 52 53 34 45 21 31 42 12 53 21 43 76 62 12 73 3 67 12 78 89 26 10 74 78 23 32 26 21 56 78 91 85 15 12 15 56 45 21 45 26 21 34 28 12 67 23 24 43 25 65 23 8 87 21 78 54 76 79 The customer service director has analysed this data to create a grouped frequency table and plotted the histogram. From this he made a series of observations regarding the time to respond to customer complaints. He now wishes to extend the analysis to use numerical methods to describe this data. (a) From the data set calculate the mean and median. (b) Repeat the analysis to calculate the standard deviation, quartiles (Q1, Q2, and Q3), quartile range, and semi interquartile range. (c) What conclusions can you draw from these results?

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter10: Statistics
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Nana AB. supplies a range of computer hardware and software to 2000 schools within a large municipal region of Spain. When Nana AB. won the contract the issue of customer service was considered to be central to the company being successful at the final bidding stage. The company has now requested that its customer service director creates a series of graphical representations of the data to illustrate customer satisfaction with the service. The following data has been collected during the last six months and measures the time to respond to the received complaint (days).
5
24
34
6
61
56
38
32

87
78
34
9
67
4
54
23

56
32
86
12
81
32
52
53

34
45
21
31
42
12
53
21

43
76
62
12
73
3
67
12

78
89
26
10
74
78
23
32

26
21
56
78
91
85
15
12

15
56
45
21
45
26
21
34

28
12
67
23
24
43
25
65

23
8
87
21
78
54
76
79


The customer service director has analysed this data to create a grouped frequency table and plotted the histogram. From this he made a series of observations regarding the time to respond to customer complaints. He now wishes to extend the analysis to use numerical methods to describe this data.

(a) From the data set calculate the mean and median.
(b) Repeat the analysis to calculate the standard deviation, quartiles (Q1, Q2, and
Q3), quartile range, and semi interquartile range.
(c) What conclusions can you draw from these results?

Expert Solution
Step 1

(a)

The mean time to respond to the customer complaints is,

Statistics homework question answer, step 1, image 1

Thus ,the mean time to respond to the customer complaints is 42.4 days.

The median is the average of the middle two values of the sorted data.

Statistics homework question answer, step 1, image 2

Thus, the median time to respond to the customer complaints is 34 days.

Step 2

(b)

The standard deviation, quartiles, quartile range and the semi-interquartile range are,

Standard deviation:

Statistics homework question answer, step 2, image 1

Thus ,the standard deviation for the time to respond to the customer complaints is 25.692 days.

First-quartile:

It is the average value of the data points that lies to the left of the median since the number data points that lie to the left of the median.

Statistics homework question answer, step 2, image 2

Thus ,Q1 is 21 days.

Third-quartile:

 It is the median value of the data points that lies to the right of the median since the number data points that lie to the right of the median is 67.

 Thus, Q3 is 67.

Inter-quartile range:

Statistics homework question answer, step 2, image 3

Thus, the inter-quartile range is 46.

Semi-interquartile range:

Statistics homework question answer, step 2, image 4

Thus, the semi-interquartile range is 23 days.

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