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Natural camphor ((+)-1R, 4R) has a specific rotation of +44,1°. If a particular sample of camphor has a rotation [a]p of +33°, what is the enantiomeric excess? The ee is: What fraction of the sample (in percent) is the (1R, 4R) enantiomer?

Natural camphor ((+)-1R, 4R) has a specific rotation of +44,1°. If a particular sample of camphor has a rotation [a]p of +33°, what is the enantiomeric excess? The ee is: What fraction of the sample (in percent) is the (1R, 4R) enantiomer?

EBK A SMALL SCALE APPROACH TO ORGANIC L
EBK A SMALL SCALE APPROACH TO ORGANIC L
4th Edition
ISBN:9781305446021
Author:Lampman
Publisher:Lampman
Chapter92: Polarimetry
Section: Chapter Questions
Problem 3P
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I have a question about this problem working on it study group my friend says the ee is already a percent and you would add the 12.5% because the remaining 25% is the race mix and s is half of the race mix. I am lost because I thought to find the ee you do ( observed rotation/ the specific rotation) which is what the majority of online sites say I got 0.748 &74.8 or 75% and they got 75 & 87 can someone please help and explain, I have also attached an image of what my professor said as well. 

Natural camphor ((+)-1R, 4R) has a specific rotation of +44.1°. 3) a) If a particular sample of camphor has a rotation [a]p of +33°, what is the enantiomeric excess? The ee is: Camphor b) What fraction of the sample (in percent) is the (1R, 4R) enantiomer? Percent (1R, 4R) is:
Transcribed Image Text:Natural camphor ((+)-1R, 4R) has a specific rotation of +44.1°. 3) a) If a particular sample of camphor has a rotation [a]p of +33°, what is the enantiomeric excess? The ee is: Camphor b) What fraction of the sample (in percent) is the (1R, 4R) enantiomer? Percent (1R, 4R) is:
The definition of ee (well, it's one way to define it) is alpha observed divided by alpha of a pure sample (concentrations and path lengths divided out in both). The second part requires that you calculate total amount of each enantiomer. If the sample is 50% ee, then 50% of the sample is a major enantiomer and the remaining 50% is racemic. Racemic is a 1:1 mixture of enantiomers, so half of the 50% racemic (25%) is the major enantiomer. With that, you calculate the total fraction of the sample that is the major enantiomer, which in the example above is 75%.
Transcribed Image Text:The definition of ee (well, it's one way to define it) is alpha observed divided by alpha of a pure sample (concentrations and path lengths divided out in both). The second part requires that you calculate total amount of each enantiomer. If the sample is 50% ee, then 50% of the sample is a major enantiomer and the remaining 50% is racemic. Racemic is a 1:1 mixture of enantiomers, so half of the 50% racemic (25%) is the major enantiomer. With that, you calculate the total fraction of the sample that is the major enantiomer, which in the example above is 75%.
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