Need to know if I did A and B correctly, and how to solve C using the same equation. 8. PCl3(g)  +  Cl2(g) --->  PCl5(g)  +  heat (a)  If the temperature is increased, the system will (shift left / shift right / no change). Circle the correct answer. MY ANSWER: SHIFTS LEFT   (b)  The equilibrium constant K for this reaction is 82.64 .  If the concentrations of PCl3(g) and Cl2(g) are both 0.0330 M at equilibrium, what is the concentration of PCl5(g)?   82.64 (k) = [PCI5] / [0.0330][0.0330] [PCI5]   = 82.64 / 1.089 x 10-3 MY ANSWER: 0.0759M For the reaction in #8, suppose the temperature was changed such that the equilibrium constant decreased to 72.58, and the equilibrium shifted until the concentration of PCl5was 0.0536.  Because PCl3 and Cl2 are reacted or produced in a mole ratio of 1:1, the concentrations are the same.  What are they?

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 2RQ: What is the law of mass action? Is it true that the value of K depends on the amounts of reactants...
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Need to know if I did A and B correctly, and how to solve C using the same equation.

8. PCl3(g)  +  Cl2(g) --->  PCl5(g)  +  heat

(a)  If the temperature is increased, the system will (shift left / shift right / no change).
Circle the correct answer. MY ANSWER: SHIFTS LEFT

 

(b)  The equilibrium constant K for this reaction is 82.64 .  If the concentrations of PCl3(g) and Cl2(g) are both 0.0330 M at equilibrium, what is the concentration of PCl5(g)?  

82.64 (k) = [PCI5] / [0.0330][0.0330]

[PCI5]   = 82.64 / 1.089 x 10-3

MY ANSWER: 0.0759M

For the reaction in #8, suppose the temperature was changed such that the equilibrium constant decreased to 72.58, and the equilibrium shifted until the concentration of PCl5was 0.0536.  Because PCl3 and Cl2 are reacted or produced in a mole ratio of 1:1, the concentrations are the same.  What are they?

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