Net-Newsers. In June 2008, the Pew ResearchFoundation sampled 3615 U.S. adults and asked abouttheir choice of news sources. They identified 13% as“Net-Newsers” who regularly get their news fromonline sources rather than TV or newspapers.a) Pew reports a margin of error of {2, for this result.Explain what the margin of error means.b) Pew’s survey included 2802 respondents contactedby landline and 813 contacted by cell phone. If thepercentage of Net-Newsers is the same in both groupsand Pew estimated those percentages separately, whichgroup would have the larger margin of error? Explain.c) Pew reports that 82% of the 470 Net-Newsers in theirsurvey get news during the course of the day, farmore than other respondents. Find a 95% confidenceinterval for this statistic.d) How does the margin of error for your confidenceinterval compare with the values in parts a and b?Explain why.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.4: Collecting Data
Problem 6E
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Net-Newsers. In June 2008, the Pew Research
Foundation sampled 3615 U.S. adults and asked about
their choice of news sources. They identified 13% as
“Net-Newsers” who regularly get their news from
online sources rather than TV or newspapers.a) Pew reports a margin of error of {2, for this result.
Explain what the margin of error means.
b) Pew’s survey included 2802 respondents contacted
by landline and 813 contacted by cell phone. If the
percentage of Net-Newsers is the same in both groups
and Pew estimated those percentages separately, which
group would have the larger margin of error? Explain.
c) Pew reports that 82% of the 470 Net-Newsers in their
survey get news during the course of the day, far
more than other respondents. Find a 95% confidence
interval for this statistic.
d) How does the margin of error for your confidence
interval compare with the values in parts a and b?
Explain why.

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