I have this data, but need help comprehending how to the missing data. Net torque ( T): ET, = 0 Tcw = Teew%3DTeew= WgrcGTew = wir1ccw% Difference between Tew and Tcew

Name: I have this data, but need help comprehending how to the missing data.
Uploaded: 2024-03-05T11:56:34.000Z
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Description: I have this data, but need help comprehending how to the missing data. Net torque ( T): ET, = 0 Tcw = Teew%3DTeew= WgrcGTew = wir1ccw% Difference between Tew and Tcew

Given data is as per question: m1=8.2×10-2 kgr1=0.247 mrCG=0.254 m

Answered: Net torque ( T): ET, = 0 Tcw = Teew %3D…

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter1: Units And Measurement

Section: Chapter Questions

Problem 81AP: Consider the equation s=s0+v0t+a0t2/2+j0t3/6+s0t4/24+ct5/120 , were s is a length and t is a time....

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I have this data, but need help comprehending how to the missing data.

Net torque ( T): ET, = 0 Tcw = Teew
%3D
Teew= WgrcG
Tew = wir1
ccw
% Difference between Tew and Tcew

Expert Solution

Step 1

Given data is as per question:

$m_{1} = 8.2 \times 10^{- 2} k g r_{1} = 0.247 m r_{C G} = 0.254 m$

Step 2

According to data in activity one;

$r_{C G a v g} = \frac{r_{C G 1} + r_{C G 2} + r_{C G 3}}{3} = \frac{0.504 + 0.503 + 0.504}{3} r_{C G a v g} = 0.504 m m_{s} = \frac{m_{s 1} + m_{s 2} + m_{s 3}}{3} = \frac{0.0789 + 0.0791 + 0.0792}{3} m_{s} = 0.0790 k g$

$\begin{array}{rcl} F_{p i n} & = & m_{s} g + m_{1} g \\ = & 0.0790 \times 9.8 + 8.2 \times 10^{- 2} \times 9.8 \\ = & 9.8 \times (0.0790 + 0.082) \\ = & 1.578 N \end{array}$

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