Newton's constant of gravitation  G is 6.67×10-11 in the system of units we use with mass in kilograms, length in meters, and time in seconds.  The radius of Earth is approximately 6.378 ×106 m, and its mass is  5.97 × 1024 kg.  With all this you can evaluate conservation of energy from Earth's surface and find an escape velocity of about 11.2 km/s from   Now suppose we wanted to orbit a spacecraft in low Earth orbit just a few hundred km above the surface.  How fast would it have to go to stay in a circular orbit?       7.9 km/s, that is about 11.2 / √2.     11.2, the same as the escape velocity     15.8, that is 11.2 * √2.     5.6, half the escape velocity

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Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!