Newton's law of cooling states that the rate of change in the temperature T(t) of a body is proportional to the difference between the temperature of the medium M(t) dT = K[M(t) – T(t)], where K is a constant. Let K = 0.04 (min) dt - 1 and the temperature of the medium be constant, M(t) = 291 and the temperature of the body. That is, kelvins. If the body is initially at 367 kelvins, use Euler's method with h = 0.1 min to approximate the temperature of the body after (a) 30 minutes and (b) 60 minutes. (a) The temperature of the body after 30 minutes is kelvins. (Round to two decimal places as needed.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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b) the temp of the body after 60 Minutes is _______ kelvin theres a part a and b please help Answer correctly asap.
Newton's law of cooling states that the rate of change in the temperature T(t) of a body is proportional to the difference between the temperature of the medium M(t)
dT
= K[M(t) – T(t)], where K is a constant. Let K = 0.04 (min)
dt
- 1
and the temperature of the medium be constant, M(t) = 291
and the temperature of the body. That is,
kelvins. If the body is initially at 367 kelvins, use Euler's method with h = 0.1 min to approximate the temperature of the body after (a) 30 minutes and (b) 60 minutes.
(a) The temperature of the body after 30 minutes is
kelvins.
(Round to two decimal places as needed.)
Transcribed Image Text:Newton's law of cooling states that the rate of change in the temperature T(t) of a body is proportional to the difference between the temperature of the medium M(t) dT = K[M(t) – T(t)], where K is a constant. Let K = 0.04 (min) dt - 1 and the temperature of the medium be constant, M(t) = 291 and the temperature of the body. That is, kelvins. If the body is initially at 367 kelvins, use Euler's method with h = 0.1 min to approximate the temperature of the body after (a) 30 minutes and (b) 60 minutes. (a) The temperature of the body after 30 minutes is kelvins. (Round to two decimal places as needed.)
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