NH,* Glycine = CH,-c00- I liter of 0.1 M glycine. pKa's = 2.34 and 9.6 c. How much 5M KOH is needed to change pH from 9 to 10 for 1 Liter of 0.1M glycine? pH = pka + log A/HA 10 = 9.6 + log A/HA so: log A/HA = 0.4 thus A/HA = 2.5 → 2.5HA = A HA + A = 0.1 M → HA + 2.5 HA = 0.1 M → 3.5HA= 0.1M so HA at pH 10 = 0.029 males/L from pH 9 HA is converted to A by adding OH", that is HA is lowered from 0.08M to 0.029M or a change of 0.051 moles 0.051 moles/5 moles/L = 0.01 L → 10 ml of 5M KOH %3D

NH,* Glycine = CH,-c00- I liter of 0.1 M glycine. pKa's = 2.34 and 9.6 c. How much 5M KOH is needed to change pH from 9 to 10 for 1 Liter of 0.1M glycine? pH = pka + log A/HA 10 = 9.6 + log A/HA so: log A/HA = 0.4 thus A/HA = 2.5 → 2.5HA = A HA + A = 0.1 M → HA + 2.5 HA = 0.1 M → 3.5HA= 0.1M so HA at pH 10 = 0.029 males/L from pH 9 HA is converted to A by adding OH", that is HA is lowered from 0.08M to 0.029M or a change of 0.051 moles 0.051 moles/5 moles/L = 0.01 L → 10 ml of 5M KOH %3D

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter8: Acids And Bases

Section8.9: How Do We Use Titrations To Calculate Concentration?

Problem 8.9P: Problem 8-9 Calculate the concentration of an acetic acid solution using the following data. Three...

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