Your goal is to make a buffer with a pH of 4.95 from acetic acid and sodium acetate. ASsume the pKa for acetic acid is 4.74. What is the volume of acetic acid added make your buffer? Report your answer to the tenths place. To do this, we use the Henderson-Hasselbach Equation pH = pkA + log (base/acid) where pkA = 4.74 for acetic acid, pH = target pH and [base] /[acid] = x/(1-x) since we don't know the concentration of the base, we will call it x the acid is just 1-x, assuming the two add up to 100% solve for x, and then you know the ml of base and acid to add.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 95AP
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Your goal is to make a buffer with a pH of 4.95 from acetic acid and sodium acetate. Assume the pKa for acetic acid is 4.74. What is the volume of acetic acid added to
make your buffer? Report your answer to the tenths place.
To do this, we use the Henderson-Hasselbach Equation
pH = pkA + log (base/acid)
where pkA = 4,74 for acetic acid,
pH = target pH
and [base) /[acid] = x/(1-x)
since we don't know the concentration of the base, we will call it x
the acid is just 1-x, assuming the two add up to 100%
solve for x, and then you know the mL of base and acid to add.
Transcribed Image Text:Your goal is to make a buffer with a pH of 4.95 from acetic acid and sodium acetate. Assume the pKa for acetic acid is 4.74. What is the volume of acetic acid added to make your buffer? Report your answer to the tenths place. To do this, we use the Henderson-Hasselbach Equation pH = pkA + log (base/acid) where pkA = 4,74 for acetic acid, pH = target pH and [base) /[acid] = x/(1-x) since we don't know the concentration of the base, we will call it x the acid is just 1-x, assuming the two add up to 100% solve for x, and then you know the mL of base and acid to add.
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