نقطتان (2) E 6V + * In the network shown in the figure, the magnitude of the current in (R1) using superposition theorem is R1 R2 8Q 8Q I 3A 3A

Q: For the circuit shown, ICQ value is pu Vcc=14V {" 220KEN Re • 22 ΚΩ 16 10pF 7-30 D output

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A: Given data, Transfer function is given as, GsHs=10ss+2 ω=0.1 rad/s

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Q: Y11 for the following circuit is V O 0.4 S O 0.5 S 3.5 S O 0.45 S www 502 592 www >0.5V₂ 202 V₂

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Q: Determine Vout for Vin=169 V, R₁-234 Ohm, R₂-28 Ohm Vin ww R₁ www R₂3 -Yout

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Q: The equation for Va(w) is + m 2jwL ) V; (co) ^ 1₁ (0) 4Ω + V₂ (10) (+1 w 492 N AV (0) ^ 1₂ (00) 20…

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Q: (B): Obtain the transfer function V₂(s)/V₁(s) of the electronic cct. shown in Fig.(3) Vi(s) Fig. (3)…

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Q: The Y parameters from the following Z parameters are [2]-[ 4.8 -0.4] ₁2 -0.4

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Q: Please show solution 2. Find the inverse Fourier transform of the following signals. (a) X(jw) =…

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Q: > * For the circuit shown, ICQ value is * input C₁ 北 10 μF O 3.02mA O 4.02mA O 2.02mA O 5.02mA…

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Q: For the circuit shown, Vc voltge is C₁ HH 10 µF O -4.48V O -3.48V Re 22% 100 kQ Rc1.2kQ C₂ H 10 pF…

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A: Given: The open loop transfer function of the system GsHs=10ss+2 ω=0.1 radsec

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Current Division Method

The generalized current divider formula is given by the following relation below,