NT2E-WBT23: VECTORS ON A GRID-VECTOR (CROSS) PRODUCT Four vectors are shown below superimposed on a grid that has arbitrary units. |î j k = 3 -2 0-k -2 -3 ---2 = 0 +3 0=k 0 0 +3 a) Using the vectors on the grid above, what vector (cross) product results in the following calculation? +10 Ĉ 9-4) k=-13k =-3k 33.7° 56.3% R b) Using the vectors on the grid above, what vector (cross) product results in the following calculation? B 10

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A). Using the vectors on the grid above, what vector (cross) product results in the following calculation? B). Using the vectors on the grid above, what vector (cross) produet results in the following calculation? Show all work
NT2E-WBT23: VECTORS ON A GRID-VECTOR (CROSS) PRODUCT
Four vectors are shown below superimposed on a grid that has arbitrary units.
by
Ĵ k
= 3 -2 0
-2 -3
= 0 +3 0
0
=(-9-4)=-
+1
A
a) Using the vectors on the grid above, what vector (cross) product results in the following
calculation?
=-13k
|=-3k
33.7°
56.3%
24
B
b) Using the vectors on the grid above, what vector (cross) product results in the following
calculation?
D
Se
x
Transcribed Image Text:NT2E-WBT23: VECTORS ON A GRID-VECTOR (CROSS) PRODUCT Four vectors are shown below superimposed on a grid that has arbitrary units. by Ĵ k = 3 -2 0 -2 -3 = 0 +3 0 0 =(-9-4)=- +1 A a) Using the vectors on the grid above, what vector (cross) product results in the following calculation? =-13k |=-3k 33.7° 56.3% 24 B b) Using the vectors on the grid above, what vector (cross) product results in the following calculation? D Se x
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