-nx(2) For n E N, consider the function fn(x) = = e on the interval [0, ∞). Let f(x) =limn→∞ f (x) for x = [0, ∞).(a) Describe the function f(x). Is it continuous on [0, ∞).(b) Show that the sequence of functions (fn) does not converge uniformly on [0, ∞).(c) Does the sequence (fn) converge uniformly on the open interval (0, ∞)?(d) Show that for any a > 0, fn converges uniformly to f on the interval [a, ∞).

Answered: Image /qna-images/answer/31999039-4532-4936-ac29-23a7c292bb47.jpg

Answered: -nx For n EN, consider the function…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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In Example 2.4.1, show that fn(x) converges to f(x) pointwise on [0, 1]. (We haveseen the convergence at x = 0, 1.) For x ∈ [0, 1] and positive integer n, let fn(x) = xn.Then limn→∞ fn(x) = f(x),, wheref(x) = 0 if 0 ≤ x < 1,1 if x = 1.This example shows that the pointwise limit of a sequence of continuous functions need not be continuous.
Let x_1 = 1/2 and, for n ≥ 1, x_(n+1) = √xn. Prove that the sequence (xn)^∞_n=1 converges and find its limit.
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Suppose that fn : [0, 1] → R is defined by fn(x) = x n. If 0 ≤ x < 1, then xn → 0 as n → ∞, while if x = 1, then x n → 1 as n → ∞. So fn → f pointwise where Although each fn is continuous on [0, 1], their pointwise limit f is not (it is discontinuous at 1). Thus, pointwise convergence does not, in general, preserve continuity.
(i) Let gn(x) =1/n(1 + x2) For any fixed x ∈ R, we can see that limgn(x) = 0 so that g(x) = 0 is the pointwise limit of the sequence (gn) on R. Is this convergence uniform? The observation that 1/(1 + x2) ≤ 1 for all x ∈ R implies that .
Suppose that F(u) denotes the DFT of the sequence of f(x)={1, 2, 3, 4}? What is the value of F(14)? (Hint: DFT periodicity)
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Suppose that a sequence of differentiable functions {fn} converges pointwiseto a function f on an interval [a,b], and the sequence {f′n}converges uniformlyto a function g on [a,b]. Then show that f is differentiable and f′(x) = g(x)on [a,b].

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