o solve ith the initial values y(0)=0 and solution get the solution, we assume nor B are solutions of the homogeneous equation this ssumption will work. Substituting y in the differential equation we obtain and B=-1/2. Next, we use the initial conditions and obtain and D=1. A=-1 y=A+Bt C=-1/2 At yFcos A+B particular complementary A=1 y-At+B C=1/2 y'(0)=-1 y(0)=-1 y'(0)=1 y'(0)=2 y"+y' - 2y = 2t Ye= Ce 2t + Det. we first find the . Since neither

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