Of 380 randomly selected medical students, 210 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

Q: ) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95%…

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Q: The newspaper conducted a survey and asked some of the city's voters which candidate they preferred…

A: For the given confidence interval, the margin of error, E is:

Q: A television station surveys 200 customers and finds that 23% of customers watch the evening news.…

A: Given data n=200 p=23% confidence level=99%

Q: uman resources managers, 71% of respondents felt they should hire new staff within the next three…

A: The Upper limit can be calculated as: Upper limit = Point estimate (sample proportion) + Margin of…

Q: Out of a sample of 500 high school students, 376 said they would prefer to have computers in every…

A: Given that x=number of people who prefer to have computers= 376 n=sample size= 500 So the point…

Q: In a survey of 2313 adults, 714 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Given, In a survey of 2313 adults, 714 say they believe in UFOs. n=2313 x=714 Sample proportion:…

Q: Out of 1,500 licensed drivers, 900 admitted that they do not like to drive at night. What is the 92%…

A: Given Information:  Total Number of drivers = 1500  Number of drivers that do not like to drive at…

Q: A random sample of 75 college students of MSU is selected and 16 are found to have motorcycles on…

A: From the given information, The sample size is 75. Out of 75 students, 16 are found to have…

Q: In a recent poll, 130 people were asked if they liked dogs, and 24% said they did. Find the margin…

A: Given, Total number of people = 130 Probability that a person likes a dog = 0.24 z value at 99%…

Q: Of 400 employees selected randomly from one company, 18.25% of them commute by carpooling. Construct…

A: The sample size n = 400. The probability p is 0.1825 The absolute value of Zα/2 is 1.96 using the…

Q: A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.…

A: The provided information is p=0.14q=1-p=1-0.14=0.86n=500E=3%=0.03p-Represents the proportion of…

Q: In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada. Calculate…

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Q: n a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: The given data is appropriate for single proportion confidence interval . because it is a large…

Q: Of 219 employees selected randomly from a company, 10% of them commute by carpooling. Construct a…

A: Given Data Sample Size, n = 219 Sample proportion = p̂= 0.10 Significance level, α…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A:

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: company check police records on 590 accident selected at random and notes that the teenagers were at…

A: The sample proportion is computed as follows: The critical value for 95% confidence level, i.e.,…

Q: Of 400 randomly selected medical students, 21 said that they planned to work in a  rural community.…

A:

Q: Of 380 randomly selected medical students, 210 said that they planned to work in a rural community.…

A: Solution: Let X be the number of medical students said that they planned to work in a rural…

Q: 95% confidence interval for the proportion of adults in the United States who say that their…

A:

Q: Commerce students were asked if they watch or listen to the state of the nation address (SONA), of…

A: Given: n= 220 ,x= 105 At 90.0 % confidence level , z score= 1.645 Need to find confidence interval…

Q: Of 2019 employees selected randomly at a company, 10% of them commute by carpooling. Construct a 90%…

A:

Q: In a survey of 1,626,773 U.S. adults, 49,311 personally identified as lesbian, gay, bisexual, or…

A:

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Q: Of the 1,000 people, 550 people used company s's smartphone and 460 people used company a's…

A: Given: n= 1000 ,x= 550.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence…

Q: In a recent poll, 480 people were asked if they liked dogs, and 48% said they did. Find the Margin…

A: Solution: From the given information, p-hat=0.48 and n=480. The confidence level is 0.90.

Q: Suppose a random sample of 459 married couples found that 307 had two or more personality…

A: Introduction - Confidence interval for two proportion CI=Sample difference ±critical difference…

Q: In a recent poll, 430 people were asked if they liked dogs, and 54% said they did. Find the margin…

A: In a recent poll, 430 people were asked if they liked dogs, and 54% said they did. Find the margin…

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: Suppose you are with a health agency that wants to estimate what percentage of Ohioans really has…

A: Given that the margin of error is 2%=0.02 Confidence level is 95% Therefore, the significance level…

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: Of 266 employees selected randomly from one company, 13.53% of them commute by carpooling. Find the…

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Q: Find a 95% confidence interval for the true population proportion.   In a poll of 1079 college…

A: The value of z at 95% confidence level is 1.96, which can be obtained by using the standard normal…

Q: Assume a nationwide random survey of 800 adults asked about attitudes toward “alternative medicine”…

A: We have given that,  Sample size (n) = 800 and Favorable cases (X) =448 Then,  We will find the 99%…

Q: A university planner wants to determine the proportion of undergraduate students who plan to attend…

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Q: Of 130 adults selected randomly from one town, 30 of them smoke. Construct a 90% confidence interval…

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Q: In a sample of 570 adults, 485 had children. Construct a 95% confidence interval for the true…

A: The sample size is 570. The number of successes is 485. We have to construct 95% confidence interval…

Q: In a recent poll, 390 people were asked if they liked dogs, and 83% said they did. Find the Margin…

A: We want to find the margin of error

Q: A survey of 360 college seniors found that 305 wish they had spent more time studying. Find a 94%…

A: Givensample size(n)=360x=305p^=xn=305360=0.8472confidence interval = 94%

Q: US Adults, 2439 say they hve contributed to a charity in the past 12 months. Construct the 95%…

A: The value of z at 95% confidence level is 1.96, which can be obtained by using the standard normal…

Q: In a sample of 510 adults, 464 had children. Construct a 95% confidence interval for the true…

A: Given that in a sample of 510 adults, 464 had children. 95% confidence level

Q: In a survey of 1219 U.S. adults, 354 said that their favorite sport to watch is football. Construct…

A: According to the given information, we have Total number of U.S. adults = 1219 354 said that their…

Q: 6) When 415 college students were surveyed, 175 said they own their car. Construct a 95% confidence…

A: Given, The sample proportion is, Critical value: Using z-table, the z-critical value at the given…

Q: In a recent poll, 570 people were asked if they liked dogs, and 14% said they did. Find the margin…

A: From the Standard Normal Table, the z value for 95% level is 1.96.

Q: If 390 people were asked if they liked dogs, and 82% said they did What is the margin of error of…

A: The sample size is 390, proportion is 0.82. Computation of critical value:…

Q: The last poll of 144 voters in Iowa shows that 19% of voters will vote for him in the Iowa…

A: From the given information,Sample size(n) = 144,Sample proportion (p) = 0.19.Confidence level (1-α)…

Q: Of 40 bank customers depositing a check, 17 received some cash back. Construct a 90 percent…

A: Introduction: The 100 (1 – α) % confidence interval for the population proportion, p is: Here, n is…

Q: Of 130 adults selected randomly from one town, 25 of them smoke. Construct a 99% confidence interval…

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Q: Of 375 randomly selected students, 30 said that they planned to work in a rural community. Find 95%…

A: Using z ditribution to construct the interval.

Q: A local health centre noted that in a sample of 400 patients, 80 were referred to them by the local…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.