of a pendulum bob suspended by a spring and allowed to swing in : Taking reference of a potential energy at the support, we write V=- mgr cos 0+ due to extention of spring 1 =- mgr cos 0+k (r-ro)?,
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Q: a cart has a mass 62 kg is subjected to a force P=328.104 N as shown to move along rough horizontal…
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- 5. Gravity is given by g = 9.81 - 3.32 X 10^-6 h m/s^2, where h is the height above sea level. An airplane is travelling at 900 km/h at an elevation of 10 km. If its weight at sea level is 40 kN, determine (a) its kinetic energy and (b) its potential energy relative to sea level. Derive with the formula below, show the cancellation, explain the step by step and draw a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.A multi-blades wind machine has power coefficient Cp 1A-0.5 A2 where A is the tip speed ratio. The rotor rotational speed w 1 (radec) and air density p= 1.2 kg/m³. a. Find Cp,max b. Find the required rotor radius R (m) in order to produce design Power P = 5042.1 ft (W): c. Find produced Power (W) for the same w, given Rotor Radius R = 6 (m) and wind speed V = 3 (m/s), assuming given wind speed is less than the design wind speed and more than the cut-in wind speed:W1 weight is dropped from height h towards W2 weight,W1=40N,W2=400N,h=200mm, k=32 kN/m.Find the maximum values of the spring force and the bending amount of W2.Consider the impact of between W1 and W2 is not flexible,it's rigid, ignore the weight of spring,and solve it using energy conversation method. I am Turkish,if my english is bad I am so sorry I did my best.Can you help me about this problem?
- 12. Steam enters a turbine with an enthalpy of 1292Btu/lb and leaves with an enthalpy of 1098 Btu/lb. The transferred heat is 13 Btu/lb. what is the work in hp for a flow of 2 lb/sec? Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.1- The internal force of the spring is Select one: a. 228.15 b. 386.10 c. 292.50 d. 473.85 e. 93.60 2- Tension in BC is Select one: a. 588.49 b. 177.25 c. 411.23 d. 216.25 e. 641.66 3- Tension in BD is Select one: a. 484.52 b. 275.68 c. 45.95 d. 547.17 e. 208.84 4- If maximum tension in cables does not exceed 975 N, the corresponding spring constant is (N/m) Select one: a. 1456.00 b. 4550.00 c. 3549.00 d. 6006.00 e. 7371.00a) The velocity ratio (VR) b) The mechanical advantage c) The efficiency, Answer in % d) The ideal effort (P1). Answer in N
- Answer no. 17, given the number 16 below. The computed Q and time in 16 are, Q= 15 862.7953 kJ, t=143. 1397 mins. Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.bucket filled with water weighing 20 kg is raised from a well of depth 20 m. If the linear density of the rope is 0.2 kg/m, the work done is _____ (Assume g = 10m/s2) a) 4000 J b) 4040 J c) 4400 J d) 4800 JCan tutor explained the questions from d,e,f more clear on the step and if possible can it do by using the formula I had learnt so far which is s = Rθ v = Rω at = Rα T=2pi x square root(L/g) fn= 1/2pi x square root (k/m)
- If a spring with elastic constant k [N/m] is deformed at distance x [m], then its potential energy is:1) An electric motor’s torque is a function of the speed at which it rotates. Many brushed AC motors have a linear toque curve as shown below. If the power output of the motor is equal to the torque (T) multiplied by the rotational speed in rad/s (w), what is the maximum power you can get out of the motor if the stall torque (Tstall) is 0.001 Nm and the no load speed (wno load) of 10,500 RPM? Give answer in Watts.ᴀ ʀᴇꜰʀɪɢᴇʀᴀᴛᴏʀ ʙᴀꜱᴇᴅ ᴏɴ ɪᴅᴇᴀʟ ᴠᴀᴘᴏʀ ᴄᴏᴍᴘʀᴇꜱꜱɪᴏɴ ᴄʏᴄʟᴇ ᴏᴘᴇʀᴀᴛᴇꜱ ʙᴇᴛᴡᴇᴇɴ ᴛʜᴇᴛᴇᴍᴘᴇʀᴀᴛᴜʀᴇ ʟɪᴍɪᴛꜱ ᴏꜰ -20 ᴅᴇɢ ᴄ ᴀɴᴅ 40 ᴅᴇɢ ᴄ . ᴛʜᴇ ʀᴇꜰʀɪɢᴇʀᴀɴᴛ ᴇɴᴛᴇʀꜱ ᴛʜᴇ ᴄᴏɴᴅᴇɴꜱᴇʀ ᴀꜱ ꜱᴀᴛᴜʀᴀᴛᴇᴅᴠᴀᴘᴏʀ ᴀɴᴅ ʟᴇᴀᴠᴇꜱ ᴀꜱ ꜱᴀᴛᴜʀᴀᴛᴇᴅ ʟɪQᴜɪᴅ . ᴛʜᴇ ᴇɴᴛʜᴀʟᴘʏ ᴀɴᴅ ᴇɴᴛʀᴏᴘʏ ᴠᴀʟᴜᴇꜱ ꜰᴏʀ ꜱᴀᴛᴜʀᴀᴛᴇᴅ ʟɪQᴜɪᴅ ᴀɴᴅᴠᴀᴘᴏʀ ᴀᴛ ᴛʜᴇꜱᴇ ᴛᴇᴍᴘᴇʀᴀᴛᴜʀᴇꜱ ᴀʀᴇ ɢɪᴠᴇɴ ɪɴ ᴛʜᴇ ᴛᴀʙʟᴇ ʙᴇʟᴏᴡ|ɪꜰ ᴛʜᴇ ᴄɪʀᴄᴜʟᴀᴛɪᴏɴ ʀᴀᴛᴇ ᴏꜰ ᴛʜᴇ ʀᴇꜰʀɪɢᴇʀᴀɴᴛ ɪꜱ 0.025 ᴋɢ/ꜱᴇᴄ , ᴛʜᴇ ʀᴇꜰʀɪɢᴇʀᴀᴛɪᴏɴ ᴇꜰꜰᴇᴄᴛ ɪꜱ ᴇQᴜᴀʟ ᴛᴏᴀ) 1.2 ᴋᴡ ʙ) 2.5 ᴋᴡ ᴄ) 3.2 ᴋᴡ ᴅ) 2.1 ᴋᴡ