12. Steam enters a turbine with an enthalpy of 1292Btu/lb and leaves with an enthalpy of 1098 Btu/lb. The transferred heat is 13 Btu/lb. what is the work in hp for a flow of 2 lb/sec? Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.

Q: m enters a turbine with an enthalpy of 1292 Bt/lbm and leaves with an enthalpy of 1098 Btu/lbm. The…

A: Given:h1=1292 Btu/lbmh2=1098 Btu/lbmQ=14 Btu/lbmm=2 lbm/sec

Q: Steam enters a turbine with an enthalpy of 1292 BTU/lb and leaves with an enthalpy 1098 BTU/lb. The…

A: Given data: h1=1292 BTU/lbh2=1098 BTU/lbQ=13 BTU/lbm˙=2 lb/sec Need to determine the work.

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Q: Steam enters a turbine with an enthalpy of 1292Btu/lb and leaves with an enthalpy of 1098 Btu/lb.…

A:

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Free Body Diagram

The system of forces acting on a body tends to either rotate it or make the body undergo motion. In general, when an external agent exerts a force on a body, the body undergoes translational motion and rotational motion. The body has six degrees of freedom under the influence of that force. Here, three degrees of freedom are from the translational motion while the other three are from the rotation motion. However, sometimes the bodies are not allowed to undergo any motion and are fixed, under such conditions the body is said to be constrained.