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The alcohol compound güven the formula below iş used in perfume making. Bromine benzeme and -1 synthesis of this compound using the necessary organı and indir chemicals show
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- Question 1 Carboxylic acids and its derivatives are reduced by sodium borohydride. True False Question 2 Less reactive derivatives cannot synthesize more reactive derivatives of RCOOH. True FalseOrganic Chemistry question; Please provide a well explained and correct answer for the following. the thiol has lower pKa compared with the alcohol in equal carbon number, which means the thiol has stronger acidity. Try to explain why -SH has such behavior in comparison to -OH.Which structure is best described as a carboxyl group? Question 5 options: a) –COOH b) –NH2 c) –OH d) None of the above
- 1. Give IUPAC names for the following compoundsWhat functional group(s) are needed to synthesis the following products (CHOOSE ALL THAT APPLY)Please include the letters with the answers. a. tertiary alcohol b. amide c. primary alcohol d. aldehyde e. secondary alcohol f. carboxylic acid g. aromatic h. ketoneQUESTION 3Starting with 2-pentyne, write the chemical equation for the synthesis of: a) Pentaneb) 2,2,3,3-tetrabromopentanec) 2,2-dibromopentaned) trans-2-pentenee) cis-2-pentene
- Give IUPAC names for the following compounds: b. c. e. f.Question 4: The reaction of propylbenzene with NBS gives: 1-bromo-3-phenylpropane 2-bromo-1-phenylpropane 1-bromo-1-phenylpropane A mixture of all three of the above compound The reaction of 1-phenyl-1-propene with HBr gives: Question 2 options: 1-bromo-3-phenylpropane 2-bromo-1-phenylpropane 1-bromo-1-phenylpropane A mixture of all three of the above compounds Question 17: The pKa of cyclopentadiene is much smaller than typical for an allylic hydrocarbon. The best explanation for this observation is: Question 17 options: Cyclopentadiene is much more stable than expected. Cyclopentadiene is much less stable than expected. The cyclopentadienyl anion is aromatic. The cyclopentadienyl anion is antiaromatic.OChem help with IUPAC names involving Ph and Bn The phenyl group (Ph-R, C6H5-R) can be formed by removing a hydrogen from benzene and attaching a substituent to where the hydrogen was removed. The benzyl group (abbv. Bn), similar to the phenyl group, is formed by manipulating the benzene ring. In the case of the benzyl group, it is formed by taking the phenyl group and adding a CH2 group to where the hydrogen was removed. Its molecular fragment can be written as C6H5CH2-R, PhCH2-R, or Bn-R. Please provide the IUPAC name for the following: (Ph)2CHC(CH3)2CC(CH2)3CH(Bn)CHO