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On 1 May 2021, 3,000 people were vaccinated and on 31 May 2021, 45,000 people were vaccinated. (a) Setting t = 0 on 1 May and t 30 on 31 May, you want to find a function whose graph looks similar to the shape above and has the same values of 3,000 at t = 0 and 45,000 at t = 30. In each of (i) to (iv) below solve for the constants a and b so that the given function goes through the above points att 0 and t 30. i. ft) = at2+ b ii. g(t) = aebt h(t) = a + bcos iii. a ilt)

On 1 May 2021, 3,000 people were vaccinated and on 31 May 2021, 45,000 people were vaccinated. (a) Setting t = 0 on 1 May and t 30 on 31 May, you want to find a function whose graph looks similar to the shape above and has the same values of 3,000 at t = 0 and 45,000 at t = 30. In each of (i) to (iv) below solve for the constants a and b so that the given function goes through the above points att 0 and t 30. i. ft) = at2+ b ii. g(t) = aebt h(t) = a + bcos iii. a ilt)

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Functions
Section8.4: More Quadratic Functions And Applications
Problem 55PS
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On 1 May 2021, 3,000 people were vaccinated and on 31 May 2021, 45,000 people were vaccinated. (a) Setting t =0 on 1 May and t = 30 on 31 May, you want to find a function whose graph looks similar to the shape above and has the same values of 3,000 at t = 0 and 45,000 at t = 30. In each of (i) to (iv) below solve for the constants a and b so that the given function goes through the above points at t = 0 and t = 30. %3D %3D |3| %3D i. f(t) = at2+ b %3D ii. g(t) = aebt %3D h(t) = a + b cos iii. %3D a j(t) = iv. %3D 1+ be-t/10
Transcribed Image Text:On 1 May 2021, 3,000 people were vaccinated and on 31 May 2021, 45,000 people were vaccinated. (a) Setting t =0 on 1 May and t = 30 on 31 May, you want to find a function whose graph looks similar to the shape above and has the same values of 3,000 at t = 0 and 45,000 at t = 30. In each of (i) to (iv) below solve for the constants a and b so that the given function goes through the above points at t = 0 and t = 30. %3D %3D |3| %3D i. f(t) = at2+ b %3D ii. g(t) = aebt %3D h(t) = a + b cos iii. %3D a j(t) = iv. %3D 1+ be-t/10
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