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- An unknown alcohol with a molecular formula of C7H14O was oxidized to an aldehyde with HOCl. When an acidic solution of the alcohol was distilled,two alkenes were obtained. The alkene formed in greater yield was determined to be 1-methylcyclohexene. The other alkene formed the original unknown alcohol when treated with BH3/THF followed by H2O2, HO-, and H2O. Identify the unknown alcohol.Alkenes can be converted to alcohols by reaction with mercuric acetate to form a β-hydroxyalkylmercury(II) acetate compound, a reaction called oxymercuration. Subsequent reduction with NaBH4 reduces the C–Hg bond to a C–H bond, forming the alkyl alcohol, a reaction called demercuration. Draw the structures of the Hg-containing compound(s) and the final alcohol product(s) formed in the following reaction sequence, omitting byproducts. If applicable, draw hydrogen at a chirality center and indicate stereochemistry via wedge-and-dash bonds.Two diastereomeric sets of enantiomers, A/B and C/D, exist for 3-bromo-2-butanol. When enantiomer A or B is treated with HBr, only racemic 2,3-dibromobutane is formed; no meso isomer is formed. When enantiomer C or D is treated with HBr, only meso 2,3-dibromobutane is formed; no racemic 2,3-dibromobutane is formed. Account for these observations.
- Each H↔H eclipsing interaction in ethane costs about 4.0 kJ/mol. How many such interactions are percent in cyclopropane? What fraction of the overall 115 kJ/mol (27.5 kcal/mol) strain energy of cyclopropane is due to torsional strain.) Which of the following compounds will be most soluble in ethanol (CH3CH2OH)? A) ethylene glycol (HOCH2CH2OH) B) hexane (CH3CH2CH2CH2CH2CH3) C) acetone (CH3COCH3)D) trimethylamine (N(CH3)3) E) A and D are soluble in ethanol.Identify the organic functional group of the reactant, the reaction type, and predict the functional group of the product. Then choose the major product from the reaction below. Water vapor is also produced during the reaction.The reactant is a(n)a. etherb. alkenec. primary alcohold. tertiary alcohole. secondary alcoholThe reaction type is :a. hydrationb. oxidationc. dehydrationd. hydrolysise. reduction (hydrogenation)The product should be a(n)a. alkeneb. alkanec. carboxylic acid and an alcohold. ketonee. aldehydeThe major product is molecule :a. Cb. Dc. Bd. A
- Identify the organic functional groups and reaction type for the following reaction if only the major product is shown.The reactant is a(n)a. alkyneb. etherc. alkened. alcohole. aromaticThe product is a(n)a. tertiary alcoholb. primary alcoholc. aldehyde d. ethere. secondary alcoholThe reaction type is :a. hydrolysisb. hydrationc. reduction (hydrogenation)d. dehydratione. oxidationI got alkene, tertiary alcohol, and hydrolysis, but I missed one of them. What are the correct answers?Molecule Type Boiling point (°C) CH3CH2CH3 Alkane -42 CH3CHO Aldehyde +21 CH3CH2OH Alcohol +78 i. Why is the boiling point of the aldehyde greater than that of the alkane?ii. Why is the boiling point of alcohol the highest?iii. Explain why the solubility of aldehydes and alcohols falls as the molecules get bigger.What are the chemical reactions for the alcohol? Choices Oxidation of primary alcoholOxidation of secondary alcoholOxidation of tertiary alcoholHydration of alkeneIntramolecular dehydrationIntermolecular dehydrationCombustionHalogenation with hydrogen halidesHalogenation with phosphorus trihalides
- #B: Methyl acetate has methoxy, -OCH3 as the remaining of the alcohol part in the ester. Isopropyl acetate has isopropoxy, -OCH(CH3)2 as the remaining of the alcohol part in the ester. -OCH(CH3)2 is more electron donating than the methoxy, -OCH3 group due to the presence of two electron-donating -CH3 group in the former. Hence saponification reaction of Isopropyl acetate is much slower than methyl acetate. Hence the rate of saponification of methyl acetate, CH3CCO2CH3 is 50 times greater than that for isopropyl acetate.Alkene is converted to alkyl halide by reaction with HCl . (T/F) Iodoform is used as an antiseptic. (T/F) Intermolecular bonding is strongest in alcohols than phenols. (T/F) Formation of blood red colour in Victor Meyer’s test indicated the presence of primary alcohol. (T/F) Fructose is a pentahydroxyketone . (T/F)Some of the most useful compounds for organic synthesisare Grignard reagents (general formula R-MgX, where X is ahalogen), which are made by combining an alkyl halide, R-X,with Mg. They are used to change the carbon skeleton of a start-ing carbonyl compound in a reaction similar to that with R-Li:.(a) What is the product, after a final step with water, of thereaction between ethanal and the Grignard reagent of bromo-benzene? (b) What is the product, after a final step with water, ofthe reaction between 2-butanone and the Grignard reagent of2-bromopropane? (c) There are often two (or more) combina-tions of Grignard reagent and carbonyl compound that will givethe same product. Choose another pair of reactants to give theproduct in (a). (d) What carbonyl compound must react with aGrignard reagent to yield a product with the -OH group at theendof the carbon chain? (e) What Grignard reagent and carbonylcompound would you use to prepare 2-methyl-2-butanol?