Q: H3CO OH 2 HCONH,
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A: The reaction has drawn with proper arrows. Please find the attachment herewith.Explanation:
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A: equilibrium constant (Ka) = 3.7 10-7pH = 3.66 pH = -log[H+]
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A: The given molecule is a bridged bicyclic compound. The two rings are attached through a bridge.
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Q: Provide mechanism with arrows and charges H3CO NaOH H₂O مسم
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Q: -H CI-CI hv CI
A: The mechanism of the reaction takes place via radical formation and involves three steps:Step 1:…
B. Choose the major product for reaction I
C. Choose the correct reagent for reaction II
A. HBr
B. Br2/hv
C. NBS/hv
D. HBr/ROOR
E. B or C
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- Calculate △G° for the equilibrium reaction below. Given: CH3NH2(aq)+H2O(l)-->CH3NH3+(aq)+-OH(aq) Kb @25°C=4.4x10-4In cells, vitamin C exists largely as its conjugate base X. X is anantioxidant because radicals formed in oxidation processes abstract thelabeled H atom, forming a new radical that halts oxidation. Draw thestructure of the radical formed by H abstraction, and explain why this Hatom is most easily removed.Please help with this calculation of this, don't know to get the n(product) Page2. please help with it too Thanks in advance