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- Two 1.2 mm thick flat copper sheets are being spot welded using a current of 6000A and a current flow time of 0.18 s. The electrodes are 5 mm in diameter. Estimate the generated in the weld zone. Take effective resistance as 150 ohm. also calculate temperature rise assuming that the heat generated is confined to the volume ogf materials directly between two electrodes and temperature is uniformly distributed.The unit melting energy for a certain sheet metal is 10J/mm^3 .The thickness of each of the two sheets to be spot-welded is = mm. To achive required strength, it is desired to form a weldnugget that is =7 mm in diameter and 3.5 mm thick. The weld duration will be set at 44 sec .If the electrical resistance between the two surfaces is 144 micro-ohms and only one half the electricity generated will be used to form the weld nugget Determine the minium current level required in this operationTwo 1.2 mm thick sheets of steel are joined by double-sided spot welding using a current of 6000A and current flow time of t = 0.15 sec. The electrodes are 3 mm in diameter and the weld spot thickness is approximately one third of the total thickness of the metal sheets. Assuming that the effective resistance in this operation is 200 micro resistance, estimate the heat generated and its distribution in the weld zone. (Take density of steel = 8600 Kg/m3 and its latent heat capacity, L =1400 J/g)
- Calculate the heat input of welded Truss if the welding current is 215 amperages, its arc voltage is 21 volts, and 15cm/min. of welding travel speed usage.An angle iron made of AISI 1040 CD steel is welded to metal as shown and loaded with a dynamic load varying between +40kN and +60kN. E70XX (Sut = 482MPa, Sy = 393MPa) will be used as the welding electrode. Find the factor of safety of the weld zone. Note: that both static and dynamic loads are applied to the source.A mild steel ammonia receiver is a cylinder 2 m in diameter with a pressure load of 1250 kPa and a design stress of 65 MPa. The lap welding tensile strength is 450 MPa and the weld -joint efficiency is assumed to be 100%. Compute the bursting pressure of the receiver in kN/m².
- A welding operation on an aluminum alloy makes a groove weld. The cross-sectional area of the weld is 30.0 mm2. The welding velocity is 4.0 mm/sec. The heat transfer factor is 0.92 and the melting factor is 0.48. The melting temperature of the aluminum alloy is 650°C. Determine the rate of heat generation required at the welding source to accomplish this weld.An RSW operation is used to join two pieces of sheet steel having a unit melting energy of 8369.85 J/cm3. The sheet steel has a thickness of 0.3125 cm. The weld duration will be set at 0.25 sec with a current of 11,000 amp. Based on the electrode diameter, the weld nugget will have a diameter of 0.75 cm. Experience has shown that 40% of the supplied heat melts the nugget and the rest is dissipated by the metal. If the electrical resistance between the surfaces is 130 micro-ohms, what is the thickness of the weld nugget assuming it has a uniform thickness?The below Figure Q1 shows an aluminium alloy sheet metal requires to be spot welded. In order for the weld to achieve its required strength, it has to be 2mm thick and the weld duration will be set at 0.3 sec. If it is assumed that the electrical resistance between the surfaces is 160 micro-ohms, and that only 40% of the electrical energy generated will be used to form the weld nugget (the rest being dissipated into the work), determine: a) The heat energy generated at the source b) The minimum current level required in this operation c) Assuming the heat transfer factor is 0.9, what would the melting factor be? d) The power density of the process, and comment on the value.
- Te - Effective throat thickness well in mm = 6 sin45° Consider the following drawing in which plate 1 is welded onto plate 2 as shown for tensile and shear loading. The plates are fillet welded with a weld thickness of 6 mm as shown for a length of 150 mm. The plates have an ultimate strength of 275 MPa and the welding was done with F70 welding electrodes, which possesses an ultimate strength of 483 MPa. Consider a partial factor of safety of 1.7 for the welded joint and determine the design strength of the weld joint, both in tension (Tdw) and in shear (Vdw) due to the forces acting on it. a) Determine the design strength of the following weld in tension ( ) due to vertical forces. b) Determine the design strength of the weld in shear ( ) due to horizontal forces. Attached pic is shear equation for calculation Tension equation for calculation is: Tdw = FyLwte /Ymwwhat are the assumption made in the design of welded jointsAssume that two 1.5-mm thick steel sheets are being spot welded at a current of 4000 A and current-flow time is 0.3 s. Using electrodes 5 mm in diameter, estimate the amount of heat generated and the amount of heat required to melt the weld nugget. Use an effective resistance of 350 un. Take u= 9,7 Joule/mm Which one of the following are correct? O a. If the electrodes were 7 mm diameter, the amount of heat generated would decrease b. The amount of heat generated by the equipment is between 1600 to 1700 Joules c. The equipment has enough power to weld the steel sheets. d. The equipment does not have enough power to weld the steel sheets e. The amount of heat required is between 700 and 750 Joules