On the Moon, there is no air resistance to slow a falling body. To demonstrate this, an astronaut releases a feather and observes it as it falls. Suppose that the height of the feather above the lunar surface is given by the equation h(t) = 2.39 - 2.65t? where t is the number of seconds since %3D the feather was released and h(t) in the height in feet. What is the velocity, in feet per second, of this feather at the moment it hits the lunar surface?

College Physics
11th Edition
ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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On the Moon, there is no air resistance to slow a falling body. To demonstrate this, an astronaut
releases a feather and observes it as it falls. Suppose that the height of the feather above the
lunar surface is given by the equation h(t) = 2.39 - 2.65t² where t is the number of seconds since
the feather was released and h(t) in the height in feet. What is the velocity, in feet per second, of
this feather at the moment it hits the lunar surface?
Enter a decimal value as the velocity that's been rounded to the nearest hundredth as in
-1.50 or 0.59 for example.
Transcribed Image Text:On the Moon, there is no air resistance to slow a falling body. To demonstrate this, an astronaut releases a feather and observes it as it falls. Suppose that the height of the feather above the lunar surface is given by the equation h(t) = 2.39 - 2.65t² where t is the number of seconds since the feather was released and h(t) in the height in feet. What is the velocity, in feet per second, of this feather at the moment it hits the lunar surface? Enter a decimal value as the velocity that's been rounded to the nearest hundredth as in -1.50 or 0.59 for example.
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