On the x axis, a point charge Q1 = +4.80E-6 C is placed at the origin x = 0.00 m, and another point charge Q2 = +6.94E-6 C is placed atx = +5.00 m. Now the third point charge Q3 = –3.60E-6 C is placed on the x axis between Q1 and Q2, and the net electric force on Q3 is measured to be zero. What is the x coordinate of Q3 (in meters)?

On the x axis, a point charge Q1 = +4.80E-6 C is placed at the origin x = 0.00 m, and another point charge Q2 = +6.94E-6 C is placed atx = +5.00 m. Now the third point charge Q3 = –3.60E-6 C is placed on the x axis between Q1 and Q2, and the net electric force on Q3 is measured to be zero. What is the x coordinate of Q3 (in meters)?

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter24: Electric Fields

Section: Chapter Questions

Problem 14PQ: A particle with charge q on the negative x axis and a second particle with charge 2q on the positive...

See similar textbooks

Similar questions

A particle with charge q on the negative x axis and a second particle with charge 2q on the positive x axis are each a distance d from the origin. Where should a third particle with charge 3q be placed so that the magnitude of the electric field at the origin is zero?
On the x axis, a point charge Q1 = +4.80E-6 C is placed at the origin x = 0.00 m, and another point charge Q2 = +1.99E-6 C is placed at x = +5.00 m. Now the third point charge Q3 = –3.60E-6 C is placed on the x axis between Q1 and Q2, and the net electric force on Q3 is measured to be zero. What is the x coordinate of Q3 (in meters)?
A point charge q1 = -4 nC is at the point x = 0.6 m, y =0.8 m, and a second point charge q2 = 6 nC is at the point x = 0.6, y = 0. If the net electric field at the origin due to these two point charges is 132 N/C, than what would be the direction in degrees counterclockwise to the positive x axis?
Two charges are fixed in place along the x-axis, q1=+4mC at the origin and q2=-1mC at x=+4cm. Without going infinitely far away, in which region(s) could a small positive "test charge" experience no net electric force?
On the x axis, a point charge Q1 = –3.32E-6 C is placed at x = –1.66 m, and another point charge Q2 = +1.59E-6 C is placed at x = +1.88 m. What is the electric force between the two charges (in Newtons; use positive sign for repulsive forces and negative sign for attractive forces)?
In a rectangular coordinate system a positive point charge q = 6.00 x 10-9 C is placed at the point x = +0.150m, y = 0, and an identical point charge is placed at x = -0.150m, y = 0. Find the x- and y-components, the magnitude, and the direction of the electric field at the origin. (with precise solution please) A. Ex = 129N/C and Ey = -510N/C with direction of 284 degrees counterclockwise from +x axis B. Ex = 2663.1 N/C and Ey = 0 to the +x direction C. Ex = 0 and Ey = 0 D. none of the above
A point charge of 7.19x10^-6 C is at the origin while a second point charge of -6.87x10^-6 C is at the coordinates (0.58,0.32) meters. In degrees relative to he positive x direction, what's the direction of the force exerted on the charge at the origin?
In a rectangular coordinate system a positive point charge q = 6.00 x 10-9 C is placed at the point x = +0.150m, y = 0, and an identical point charge is placed at x = -0.150m, y = 0. Find the x- and y-components, the magnitude, and the direction of the electric field at x = 0.300 m, y = 0. (with precise solution please) A. Ex = 129N/C and Ey = -510N/C with direction of 284 degrees counterclockwise from +x axis B. Ex = 2663.1 N/C and Ey = 0 to the +x direction C. Ex = 0 and Ey = 0 D. none of the above
A point charge q = -0.55 nC is fixed at the origin. Where musta proton be placed in order for the electric force acting on it to beexactly opposite to its weight? (Let the y axis be vertical and the xaxis be horizontal.)
Three point charges are arranged along the x-axis. Charge q1 = +3.00 μC is at the origin, and charge q2 = -5.00 μC is at x = 0.200 m . Charge q3 = -8.00 μC . A. Where is q3 located if the net force on q1 is 7.00 N in the −x direction?
A point charge q1 = +5.00 μC is fixed in place at x = 0, and a point charge q2 = −3.50 μC is fixed at x = −20.0 cm. At what value of x can we place a point charge q3 = −6.90 μC so that the net electric force on q1 due to q2 and q3 is zero?
Three point charges are located at the vertices of an equilateral triangle. Calculate the magnitude of the net electric force acting on q1, where q1 = +7.00muC, q2 = +2.00 muC, and q3 = -4.00 muC.