One chromosome of a homologous pair carries the genes Jam K. The othen chromosome of the pair carrieo the genes jand k at corresponding loci. Crossing results in exchange of chromosome segmut of gamutes combinations of A "recombinaut and production with genes. new type gamete resulting from this cross over might contain: A-Jand K D-K and k B-J and j E-i and K and k
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- For each of the terms in the left column, choose thebest matching phrase in the right column.a. reciprocal translocation 1. lacking one or morechromosomes or having oneor more extra chromosomesb. gynandromorph 2. movement of short DNAelementsc. pericentric 3. having more than two completesets of chromosomesd. paracentric 4. exact exchange of parts of twononhomologous chromosomese. euploids 5. excluding the centromeref. polyploidy 6. including the centromereg. transposition 7. having complete sets ofchromosomesh. aneuploids 8. mosaic combination of maleand female tissueA normal female is discovered with 45 chromosomes, one ofwhich exhibits a Robertsonian translocation containing most ofchromosomes 18 and 21. Discuss the possible outcomes in heroffspring when her husband contains a normal karyotype.in the experiment of following chromosomal dna mvement througgh meiosis, why. do you use non-sister chromatids to demobstrate crossing over? what combinatiobns of alleles could result from a crossover between BD and bd chromosomes? Identify two ways that meiosis contributes to genetic recombination. Why is it necessary to reduce the number of chromosomes in gametes, but not in other cell?
- A male Drosophila from a wild-type stock is discovered to haveonly seven chromosomes, whereas normally 2n = 8. Closeexamination reveals that one member of chromosome IV (thesmallest chromosome) is attached to (translocated to) the distalend of chromosome II and is missing its centromere, thusaccounting for the reduction in chromosome number. (a) Diagram all members of chromosomes II and IV duringsynapsis in meiosis I.. Chromosome 3 of corn carries three loci (b for plant-color booster, v for virescent, and lg for liguleless). A testcross of triple recessives with F1 plants heterozygous forthe three genes yields progeny having the followinggenotypes: 305 + v lg, 275 b + +, 128 b + lg, 112 + v +,74 + + lg, 66 b v +, 22 + + +, and 18 b v lg. Give the genesequence on the chromosome, the map distances between genes, and the coefficient of coincidence.The normal sequence of nine genes on a certainDrosophila chromosome is 123 • 456789, where the dotrepresents the centromere. Some fruit flies were foundto have aberrant chromosomes with the followingstructures:a. 123 • 476589 c. 1654 • 32789b. 123 • 46789 d. 123 • 4566789Name each type of chromosomal rearrangement, anddraw diagrams to show how each would synapse withthe normal chromosome.
- The karyotype of a young girl who is affected with familialDown syndrome revealed a total of 46 chromosomes. Her olderbrother, however, who is phenotypically unaffected, actually had45 chromosomes. Explain how this could happen. What wouldyou expect to be the numbers of chromosomes in the parents ofthese two children?A couple planning their family are aware that through the pastthree generations on the husband’s side a substantial numberof stillbirths have occurred and several malformed babies wereborn who died early in childhood. The wife has studied geneticsand urges her husband to visit a genetic counseling clinic,where a complete karyotype-banding analysis is performed.Although the tests show that he has a normal complement of46 chromosomes, banding analysis reveals that one memberof the chromosome 1 pair (in group A) contains an inversioncovering 70 percent of its length. The homolog of chromosome1 and all other chromosomes show the normal bandingsequence. Question: How would you explain the high incidence of paststillbirths?A couple planning their family are aware that through the pastthree generations on the husband’s side a substantial numberof stillbirths have occurred and several malformed babies wereborn who died early in childhood. The wife has studied geneticsand urges her husband to visit a genetic counseling clinic,where a complete karyotype-banding analysis is performed.Although the tests show that he has a normal complement of46 chromosomes, banding analysis reveals that one memberof the chromosome 1 pair (in group A) contains an inversioncovering 70 percent of its length. The homolog of chromosome1 and all other chromosomes show the normal bandingsequence. Question: What can you predict about the probability of abnormality/normality of their future children?
- A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) What kind of chromosomal aberration is shown?I. In humans, chromosome 16 sometimes has a heavilystained area in the long arm near the centromere. Thisfeature can be seen through the microscope but has noeffect on the phenotype of the person carrying it.When such a “blob” exists on a particular copy ofchromosome 16, it is a constant feature of that chromosome and is inherited.A couple conceived a child, but the fetus hadmultiple abnormalities and was miscarried. When thechromosomes of the fetus were studied, it was discovered that it had three copies of chromosome 16 (it wastrisomic for chromosome 16), and that two of thethree chromosome 16s had large blobs. Bothchromosome 16 homologs in the mother lacked blobs,but the father was heterozygous for blobs. Which parent experienced nondisjunction, and in which meioticdivision did it occur?Two chromosomes have the following orders for their genes:Normal: A B C centromere D E F G H IAbnormal: A B G F E D centromere C H IDoes the abnormal chromosome have a pericentric or a paracentricinversion? Draw a sketch showing how these two chromosomeswould pair during prophase of meiosis I.