Can you help me, i need a shortcut on how to know when should i use cosine or sine.here's the problem and the solutionOne morning, Connie walks from her house to go to a store that is 500 ft, S 40o W from her house. She starts walking 120 ft, SW; then continues walking 100 ft, 10o S of E; then sees a friend who is 700 ft, 30o N of E from where she is.What is her friend’s location, (magnitude and direction) relative to her house? (Ans. 667.54 ft, 21.79o N of E)From her friend’s location, how far and in what direction should Connie walk to finally get to the store? (Ans. 1133.08 ft, 33.83o S of W) HF720'700'100.30a) HF = ?HFx, =Rx%3DHFx- (20 coS 45 + 100 Cos w † Y00 Cas 20G19.85'+%3DHFy = RyHify* - 120 Si'n 45 - 100 Si'no † 100 Si'n 3 Ode47. 78' ↑HF =+(247. 7932G67. 57'tan-'I HFytun - 347. 1e619.8521. 79° NZEHfxb)F667. 54500'40"PSFSx = Rx = {X667,54 HF = V G19.85)? +(2r7. 183²G67.54tun - 47. 78619.8521. 79° NZEHfxb)F667.54500'PSFS, = Rx = {X500 Sin 40667.54%3D941. 23- Ey- - S00 cos46 - 667.54 SinI-79630. 92'F Sy = RyFS : y(941. 23 )² + 1630.8272 = 133. 07'-i b30.82B- tan33, 83' Sf W941.23

Let Connie's house be at the origin so first she walks A=120 ft (SW) then B=100 ft (10o South of…

Answered: One morning, Connie walks from her…

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Can you help me, i need a shortcut on how to know when should i use cosine or sine.

here's the problem and the solution

One morning, Connie walks from her house to go to a store that is 500 ft, S 40^oW from her house. She starts walking 120 ft, SW; then continues walking 100 ft, 10^o S of E; then sees a friend who is 700 ft, 30^oN of E from where she is.
1. What is her friend’s location, (magnitude and direction) relative to her house? (Ans. 667.54 ft, 21.79^oN of E)
2. From her friend’s location, how far and in what direction should Connie walk to finally get to the store? (Ans. 1133.08 ft, 33.83^oS of W)

HF
720'
700'
100.
30
a) HF = ?
HFx, =
Rx
%3D
HFx
- (20 coS 45 + 100 Cos w † Y00 Cas 20
G19.85'+
%3D
HFy = Ry
Hify
* - 120 Si'n 45 - 100 Si'no † 100 Si'n 3 O
de47. 78' ↑
HF =
+(247. 7932
G67. 57'
tan-'I HFy
tun - 347. 1e
619.85
21. 79° NZE
Hfx
b)
F
667. 54
500'
40"
PS
FSx = Rx = {X
667,54

HF = V G19.85)? +(2r7. 183²
G67.54
tun - 47. 78
619.85
21. 79° NZE
Hfx
b)
F
667.54
500'
PS
FS, = Rx = {X
500 Sin 40
667.54
%3D
941. 23
- Ey
- - S00 cos46 - 667.54 SinI-79
630. 92'
F Sy = Ry
FS : y(941. 23 )² + 1630.8272 = 133. 07'
-i b30.82
B- tan
33, 83' Sf W
941.23

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