One way to make chlorine is to let manganese dioxide, MnO2, react with hydrochloric acid according to the following equation. 4HCI + MnO2-- Cl2+ MnCl2 + 2H2O What is the minimum volume (in mL) of 6.24 M HCI needed to prepare 521.4 mL of dry chlorine when the gas is obtained at 28.3 °C and 779 torr?

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter6: The Gaseous State
Section: Chapter Questions
Problem 6.131QE
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One way to make chlorine is to let manganese dioxide, MnO2, react with hydrochloric acid according to the following equation.
4HCI + MnO2- Cl2 + MnCl2 + 2H2O
What is the minimum volume (in mL) of 6.24 M HCI needed to prepare 521.4 mL of dry chlorine when the gas is obtained at 28.3 °C and
779 torr?
mL
Transcribed Image Text:One way to make chlorine is to let manganese dioxide, MnO2, react with hydrochloric acid according to the following equation. 4HCI + MnO2- Cl2 + MnCl2 + 2H2O What is the minimum volume (in mL) of 6.24 M HCI needed to prepare 521.4 mL of dry chlorine when the gas is obtained at 28.3 °C and 779 torr? mL
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