One way to remove heavy metal ions from water is by treatment with sodium carbonate. Calculate the mass of the precipitate that wil form and the concentration of Mn2* remaining in solution after 0.654 L of a solution that contains Mn2* at 3.25 × 102 M is mixed with 0.472 L of 0.742 M Na2CO3 solution. (Ksp for MNCO3 is 2.2 × 10-11.) g of the precipitate [Mn2*] = i x 10 i M

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section17.5: Precipitation Reactions
Problem 17.13CYU
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One way to remove heavy metal ions from water is by treatment with sodium carbonate. Calculate the mass of the precipitate that will
form and the concentration of Mn2* remaining in solution after 0.654 L of a solution that contains Mn2+ at 3.25 × 10² M is mixed with
0.472 L of 0.742 M Na2CO3 solution. (Ksp for MnCO3 is 2.2 × 10-11)
g of the precipitate
[Mn2*] = i
х 10
i
M
Transcribed Image Text:One way to remove heavy metal ions from water is by treatment with sodium carbonate. Calculate the mass of the precipitate that will form and the concentration of Mn2* remaining in solution after 0.654 L of a solution that contains Mn2+ at 3.25 × 10² M is mixed with 0.472 L of 0.742 M Na2CO3 solution. (Ksp for MnCO3 is 2.2 × 10-11) g of the precipitate [Mn2*] = i х 10 i M
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