One year consumers spent an average of S23 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is $5. Complete parts (a) through (c) below. a. What is the probability that a randomly selected person spent more than $24? P(X> $24) = 0.4207 (Round to four decimal places as needed.) b. What is the probability that a randomly selected person spent between $10 and $20? P($10

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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One year consumers spent an average of $23 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is $5. Complete parts (a) through (c) below.
a. What is the probability that a randomly selected person spent more than $24?
P(X> $24) = 0.4207 (Round to four decimal places as needed.)
b. What is the probability that a randomly selected person spent between $10 and $20?
P($10 <X< $20) =
0.2696
(Round to four decimal places as needed.)
c. Between what two values will the middle 95% of the amounts of cash spent fall?
The middle 95% of the amounts of cash spent will fall between X =$ 13.20 and X = $ 32.80
(Round to the two decimal places as needed.)
Transcribed Image Text:One year consumers spent an average of $23 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is $5. Complete parts (a) through (c) below. a. What is the probability that a randomly selected person spent more than $24? P(X> $24) = 0.4207 (Round to four decimal places as needed.) b. What is the probability that a randomly selected person spent between $10 and $20? P($10 <X< $20) = 0.2696 (Round to four decimal places as needed.) c. Between what two values will the middle 95% of the amounts of cash spent fall? The middle 95% of the amounts of cash spent will fall between X =$ 13.20 and X = $ 32.80 (Round to the two decimal places as needed.)
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