I only need help with the average molarity of KMnO4 solution (M) it must be a number. Reaction equation:2 MnO4− + 5 C2O42− + 16 H+ → 2 Mn2+ + 10 CO2 + 8 H2O Molarity of Na2C204 solution (M)0.02336000.02336TITRATION DATAIn the next part of the experiment, you used the standard solution ofsodium oxalate to standardize a solution of potassium permanganate,KMNO4. The potassium permanganate was the titrant. Please completethe table below.Trial 1Trial 2Volume of Na2C2O4 solution pipetted (mL)25.0025.00Initial burette reading (mL)21.1021.10Final burette reading (mL)50.0036.80Titre (mL)28.9015.70MOLARITY OF POTASSIUM PERMANGANATE SOLUTIONYou now have all of the information you need to calculate the molarity ofyour potassium permanganate solution.Trial 1Trial 2Molarity of KMnO4 solution (M)8.083045 x 1030.0148789Average molarity of KMNO4 solution (M)0.0114809unroundedAverage molarity of KMNO4 solution (M)Arounded

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only need help with the average molarity of KMnO4 solution (M) it must be a number. Reaction equation: 2 MnO4− + 5 C2O42− + 16 H+ → 2 Mn2+ + 10 CO2 + 8 H2O

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

ChapterA1: Evaluation Of Analytical Data

Section: Chapter Questions

Problem A1.22QAP

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Dissolved 0.273 grams of pure sodium oxalate (Na2C204) in distilled water and added sulfuric acid and titration the solution at 70 °C by using 42.68 ml of KMNO4 solution and has exceeded end point limits by using 1.46 ml of standard oxalic acid (H2 C204) with 0.1024 N. Calculate the normlity of KMNO4. Note that the molecular weight of sodium oxalate (Na2C204) = 134 and its equivalent weight = 67 * %3D
Q1. Dissolved 0.273 grams of pure sodium oxalate (Na2C0.) In distilled water and added sulfuric acid and titration the solution at 70 ° C by using 42.68 ml of KMnO, solution and has exceeded end point limits by using 1.46 ml of oxalic acid (H , C, 0.) With 0.1024 N. Calculate the normlity of KMnO .. Note that the molecular weight of sodium oxalate (Na, C, 0.) = 134 and its equivalent weight = 67
00 mL of a diprotic acid primary standard solution was accurately prepared to a concentration of 0.1431 M. Three samples of this primary standard solution were used as samples in a titration to standardize an aqueous solution of sodium hydroxide, NaOH, which would be used as a titrant. Using the following table of data for the titration of the primary standard acid with NaOH, calculate the average concentration of NaOH. Trial # Volume of primary standard Initial titrant volume Final titrant volume 1 10.00 mL 8.21 mL 27.22 mL 2 10.00 mL 27.22 mL 46.23 mL 3 10.00 mL 30.28 mL 49.29 mL 0.1506 M 0.0753 M 0.0376 M 0.1431 M 0.0526 M
1. Why is there a need to correct conductivity of the sample solution?2. Cite three possible sources of error in the experiment and discuss their effects on the computed ionization constant of the acetic acid. (See details below----- literature value- Ki, acetic acid= 1.75 x 10^-5). 3. What is the effect of dilution on the fraction of the acetic acid ionized?
The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463
You are given the suggestion that a 0.15 ppm quinine aqueous solution is a good concentration to shoot for in the experiments, but quinine fluoresces best when it is acidified to 0.10 M H2SO4. Describe how to make 100 mL of the recommended solution starting with quinine sulfate (actually, quinine hemisulfate salt monohydrate). Assume you also have 1.0 M sulfuric acid and de-ionized water.
A 25.00 mL sample of an aqueous solution Y is extracted with 50.00 mL of hexane. After extraction, it was found that 94.12% of solute Y was successfully removed from the aqueous solution. Calculate: i. The distribution constant for this separation The initial concentration of Y if 1.77 mmol Y remains in aqueous solution after extraction. iii. The concentration of Y in BOTH phases after extraction
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If 30.0 mL of water that is 0.0500 M in Q is to be extracted with four 10.0-mL portions of an immiscible organic solvent, what is the minimum distribution coefficient that allows transfer of all but the following percentages of the solute to the organic layer: (a) 1.00 X10-24 (b) 1.00 X10-22
Although other solvents are available, dichloromethane(CH₂Cl₂) is still often used to “decaffeinate” drinks because thesolubility of caffeine in CH₂Cl₂ is 8.35 times that in water.(a) A 100.0-mL sample of cola containing 10.0 mg of caffeine is extracted with 60.0 mL of CH₂Cl₂. What mass of caffeine re-mains in the aqueous phase? (b) A second identical cola sampleis extracted with two successive 30.0-mL portions of CH₂Cl₂.What mass of caffeine remains in the aqueous phase after each extraction? (c) Which approach extracts more caffeine?
The first goal is to make the oxalic acid standard solution. You measure 1.5232 g of oxalic acid on an analytical balance, add it to a 250-mL volumetric flask and add deionized H2O to a final volume of 250.0 mL. Molar mass of H2C2O4•2H2O = 126.07 g/mol Mass of H2C2O4•2H2O = 1.5232g Volume of H2C2O4•2H2O solution = 250.0mL What is the Molarity H2C2O4 standard solution ?
Q1. Dissolved 0.273 grams of pure sodium oxalate (Na,C,O.) in distilled water and added sulfuric acid and titration the solution at 70 ° C by using 42.68 ml of KMNO, solution and has exceeded end point limits by using 1.46 ml of standard oxalic acid (H; C;O.) with 0.1024 N. Calculate the normlity of KMN0.. Note that the molecular weight of sodium oxalate (Na,C,O.) = 134 and its equivalent weight = 67