Question
Asked Sep 23, 2019
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Only two horizontal forces act on a 4.3 kg body. One force is 6.9 N, acting due east, and the other is 2.2 N, acting 28° north of west. What is the magnitude of the body's acceleration?

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Expert Answer

Step 1

First horizontal force

Second horizontal force

Net force

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F 6.9 i F2-(2.2 cos 28 )i F,2 (2.2 sin 28') F(F-F,j

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Step 2

Net force

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F (6.9 2.2cos28 )i +2.2 sin 28'j -(6.9-1.9431.033j 4.957i 1.033

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Step 3

Magnitude of the body&rsq...

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ΣF-m F = ma ΣΕ F a = m 4.957i 1.033j a= 4.3 =1.153i0.24j

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