Consider two data sets.(Refer to screenshot) Consider two data sets.Set A: n = 5; x = 4Set B: n = 50; x = 4ΣΣx = nx. To compute x for the new data set, add 20 tox of the original(a) Suppose the number 20 is included as an additional data value in Set A. Compute x for the new data set. Hint:data set and divide by 6. (Round your answer to two decimal places.)(b) Suppose the number 20 is included as an additional data value in Set B. Compute x for the new data set. (Round your answer to two decimal places.)(c) Why does the addition of the number 20 to each data set change the mean for Set A more than it does for Set B?O Set B has a smaller number of data values than set A, so to find the mean of B we divide the sum of the values by a smaller value than for A.O Set B has a smaller number of data values than set A, so to find the mean of B we divide the sum of the values by a larger value than for A.O Set B has a larger number of data values than set A, so to find the mean of B we divide the sum of the values by a smaller value than for A.O Set B has a larger number of data values than set A, so to find the mean of B we divide the sum of the values by a larger value than for A.

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Description: Consider two data sets.(Refer to screenshot) Consider two data sets.Set A: n = 5; x = 4Set B: n = 50; x = 4ΣΣx = nx. To compute x for the new data set, add 20 tox of the original(a) Suppose the number 20 is included as an additional data value in Set

The mean formula is, x=∑xn Now, x=∑xn4=∑x5∑x=20 Now, If one score of X = 20 is added to the sample,…

Answered: onsider two data sets. (Refer to…

MATLAB: An Introduction with Applications

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Author:Amos Gilat

Publisher:Amos Gilat

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Consider two data sets.

(Refer to screenshot)

Expert Solution

Step 1

The mean formula is,

$x = \frac{\sum_{}^{} x}{n}$

Now,

$x = \frac{\sum_{}^{} x}{n} 4 = \frac{\sum_{}^{} x}{5} \sum_{}^{} x = 20$

Now, If one score of X = 20 is added to the sample, then n = 5+1=6. The value for the new mean is,

$x = \frac{\sum_{}^{} x}{n} x = \frac{20 + 20}{6} x = 6.66666 x = 6.67$

Hence, the value for the new mean is 6.67.

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