ou are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals.   From a random sample of 49 business​ days, the mean closing price of a certain stock was ​$109.33.  Assume the population standard deviation is ​$11.42.   The 90% confidence interval is

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 90%…

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Q: The prices of used books at a large college bookstore are normally distributed. If a sample of 23…

A: From the provided information, Sample size (n) = 23 Sample mean (x̅) = $27.50 Sample standard…

Q: s. A sample of 250 observations is selected from a normal population with a popula- tion standard…

A: a) Compute the standard error of the sample mean by substituting σ=25 and n=250 in the formula:…

Q: given n=31 , s=7, Xbar= 14 for an 80% confidence interval find,  standard error margin of error

A: From the given information, the sample size is n=31, the sample mean is x-bar=14 and the sample…

Q: Use the given confidence interval to find the population proportion margin of error  0.09<?<0.33

A: Form the given data we have, p^+MOE = 0.33           ......(1)p^-MOE = 0.09           ......(2)

Q: 1. The mean and standard deviation for the quality grade point averages of a random sample of 36…

A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Determine the sample size needed to construct a 95% confidence interval for the population mean, μ,…

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Q: Given a sample size of 400 with a mean of 80 and the population standard deviation is found to be 35…

A: We have given that,  Sample mean (x̄) = 80, population standard deviation (σ) = 35 and sample size…

Q: Determine the sample size needed to construct a 95% confidence interval for the population mean, μ,…

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Q: Construct the indicated confidence interval for the difference between the two population means.…

A: We have given the amount of time spent watching television by women and by men- For sample 1 for…

Q: mean = 9.4285 Standard deviation= 2.0188 count= 35 students 1. Give and interpret the 95% confidence…

A: From the given information,Mean (x-bar) = 9.4285Standard deviation (σFrom the given information,Mean…

Q: Assume that the TI generated a confidence interval for the population mean, 136 &lt; μ &lt;150 What…

A: The confidence interval for the population mean generated by TI is 136 &lt; µ &lt; 150.The point…

Q: Construct the indicated confidence interval for the difference between the two population means.…

A: Solution  We find confidence interval by excel

Q: For a group of 45 students taking a PSDTF test, the mean heart rate was 96 beats per minute, and the…

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Q: Thirty randomly selected students took the calculus final. If the sample mean was 74.2 and the…

A: From the provided information, Sample size (n) = 30 Sample mean (x̅) = 74.2 Standard deviation (s) =…

Q: The average sa!lary of 64 employee was 5400 and the sample standard deviation was 260. Find the 95%…

A: Solution

Q: Given a mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95 %…

A: A mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95% confidence…

Q: he head librarian at the Library of Congress has asked her assistant for an interval estimate of the…

A: We want to find the value of n  Given  740≤μ≤920 σ=150, ɑ=0.05

Q: If the sample mean is 70 and the standard error of the sample mean is 8, what will be the 90%…

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Q: The average salary of 64 employee was 5400 and the sample standard deviation was 270. Find the 90%…

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Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 95%…

A: It's a t distribution as the population standard deviation is unknown

Q: Construct the confidence interval for the population mean  c=0.95, x=8.7 standard deviation=0.8 and…

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Q: An agriculture publication daims that the population mean of the birth weights for all Alpine goats…

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Q: Estimate the mean of the population by constructing a 95% confidence interval

A: Given that Sample size n = 25 Sample mean = 150 Population SD = 12 The critical value of Z at 95%…

Q: The average daily volume of a computer stock in 2011 was u= 35.1 million shares, according to a…

A:

Q: The average salary of 64 employee was 5400. Using historical data, we will assume that the…

A: Given; Number of employee = 64 Average salary=5400 Standard deviation = 280.

Q: ou are given teh sample mean and the population standard deviation. Use this information to…

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Q: In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96%…

A: Given information: n = 80 μ=50 96% confidence interval for the mean number of texts handled by teens…

Q: Assume that you want to construct a​ 95% confidence interval estimate of a population mean. Find an…

A: 95% CI  for μE=3.4S=55.3n=?For 95% CI,  P(-z&lt;μ&lt;z)=0.95  ∴z=1.96       ∵z table

Q: Using the information provided below, calculate the confidence intervals for both Student B Mean:…

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Q: A simple random sample of 41 Veterans Day celebrations was selected and the number of children…

A: (14) Obtain the 98% confidence interval for the mean number of children attending all 2017 Veterans…

Q: TD Ameritrade claims that the mean price charged for a trade of 100 shares at $50 per share is at…

A: For 90% confidence level,α=1-90%=1-0.9=0.1 The value of z at α=0.1 in lower tail is 1.282.

Q: The annual earnings​ (in dollars) of 35 randomly selected microbiologists are shown in the data…

A: Given information: The annual earnings (in dollars) of n = 35 randomly selected microbiologists are…

Q: Suppose that you wanted to estimate the population mean amount spent eating out per week by…

A: The question is about sample size estimation Given: Sample std. deviation = 200 dollars Margin of…

Q: for a sample of 57 that has a mean of 6200 and a standard deviation of 254, calculate the 95%…

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Q: or a sample of 121 that has a mean of 6540 and a standard deviation of 780, calculate the 90%…

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Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

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Q: A study is to be conducted to estimate the daily water consumption per person. If the population…

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Q: Given that the 84% confidence interval for the waiting time (in minutes) of emergency room patients…

A: Point estimate =? Margin of error =?

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 260. Find the 90 %…

A:

Q: answer a,b,c A random sample of 70 observations from a normally distributed population possesses a…

A: It is given that the summary statistics are as follows: Part (a): Confidence interval for µ:…

Q: If n=25 and the sample standard deviation is 15, construct a 95% confidence interval for the true…

A: The confidence interval is used to estimate the population parameter with the help of a sample…

Q: Compute a 95% confidence interval for the true population mean given the following  10 data that…

A: Given, Sample size = 10 Sample mean = 15.3 Sample standard deviation = 3.5   Since the population…

Q: If a sample of 4 fish from my pond has mean weight 157 grams with a standard deviation of 8.3 grams…

A: Given: n=4, x=157 and s=8.3   At 99% confidence level, the value of z is 2.576.

Q: A cell phone company claims that the average time a person spends on their phone is 12.8 hours a…

A: It is given that the average time spent on phone is 12.2 hours per week and standard deviation is…

Q: ple mean of 75, population standard deviation of 5, and n = 100, Estimate the mean of the population…

A: AS the population standard deviation is known, we will use z -distribution. The critical z-value for…

Q: Use the given data to find the 95% confidence interval estimate of the population mean ?. Assume…

A: Solution-: Given: We find 95% C.I. for  the population mean

Q: A medical devices company wants to know the number of hours its MRI machines are used per day. A…

A: Given information- Population standard deviation, σ = 4 hours Confidence interval = 0.98…

Q: With a given sample of n=15, x=8900, and s=500, construct 99 percent confidence intervals for…

A: We have given that  n=15, xbar=8900, and s=500 Find the 99% confidence interval

Q: The average weight of 35 randomly selected compact automobiles was 2680 pounds. The sample standard…

A: From the provided information, Sample size (n) = 61 Sample mean (x̅) = 2680 Sample standard…