Oul answer is partially correct. Monochromatic light of wavelength 515 nm is incident on a narrow slit. On a screen 2.76 m away, the distance between the second diffraction minimum and the central maximum is 1.27 cm. (a) Calculate the angle of diffraction 0 of the second minimum. (b) Find the width of the slit. (a) Number 0.311391639 Units (degrees) (b) Number 3.089026772 Units nm

University Physics Volume 3
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ISBN:9781938168185
Author:William Moebs, Jeff Sanny
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Chapter4: Diffraction
Section: Chapter Questions
Problem 39P: When a monochromatic light of wavelength 430 nm incident on a double slit of slit separation 5 m,...
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Your answer is partially correct.
Monochromatic light of wavelength 515 nm is incident on a narrow slit. On a screen 2.76 m away, the distance between the second
diffraction minimum and the central maximum is 1.27 cm. (a) Calculate the angle of diffraction 0 of the second minimum. (b) Find the
width of the slit.
(a) Number
0.311391639
Units
° (degrees)
(b) Number
3.089026772
Units
nm
Transcribed Image Text:Your answer is partially correct. Monochromatic light of wavelength 515 nm is incident on a narrow slit. On a screen 2.76 m away, the distance between the second diffraction minimum and the central maximum is 1.27 cm. (a) Calculate the angle of diffraction 0 of the second minimum. (b) Find the width of the slit. (a) Number 0.311391639 Units ° (degrees) (b) Number 3.089026772 Units nm
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