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Over the years, the mean customer satisfaction rating at a local restaurant has been 85. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 85. In a sample of 42 customers chosen at random, the mean customer rating is 84.1. Assume that the population standard deviation of customer ratings is 5.2. Is there enough evidence to support the caim that the mean customer rating is different from 85? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis H and the alternative hypothesis H,. O

Over the years, the mean customer satisfaction rating at a local restaurant has been 85. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 85. In a sample of 42 customers chosen at random, the mean customer rating is 84.1. Assume that the population standard deviation of customer ratings is 5.2. Is there enough evidence to support the caim that the mean customer rating is different from 85? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis H and the alternative hypothesis H,. O

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Over the years, the mean customer satisfaction rating at a local restaurant has been 85. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 85. In a sample of 42 customers chosen at random, the mean customer rating is 84.1. Assume that the population standard deviation of customer ratings is 5.2. Is there enough evidence to support the claim that the mean customer rating is different from 85? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H. O<O OSO H: I D=D (b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a "Z-test"). Here is some other informnation to help you with your test. Z0 025 is the value that cuts off an area of 0.025 in the right tail.
Transcribed Image Text:Over the years, the mean customer satisfaction rating at a local restaurant has been 85. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 85. In a sample of 42 customers chosen at random, the mean customer rating is 84.1. Assume that the population standard deviation of customer ratings is 5.2. Is there enough evidence to support the claim that the mean customer rating is different from 85? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H. O<O OSO H: I D=D (b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a "Z-test"). Here is some other informnation to help you with your test. Z0 025 is the value that cuts off an area of 0.025 in the right tail.
-3 -2 3. (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the management. Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal 85. Since the value of the test statistic lies in the rejection region, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal 85. Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal 85. Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal 85.
Transcribed Image Text:-3 -2 3. (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the management. Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal 85. Since the value of the test statistic lies in the rejection region, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal 85. Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal 85. Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal 85.
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