P(A) = 0.2 P(B) = 0.4 P(B| A) = 0.24 %3D %3D Round solutions to three decimal places, if necessary. If A and B are assumed to be dependent events, P(A and B) If A and B are assumed to be independent events, P(A and B) 0.6 If A and B are assumed to be dependent and mutually non-exclusive events, P(A or B)= If A and B are assumed to be dependent and mutually exclusive events, P(A or B)

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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P(A) = 0.2
P(B) =
0.4
P(B| A) = 0.24
Round solutions to three decimal places, if necessary.
If A and B are assumed to be dependent events,
P(A and B) =
If A and B are assumed to be independent events,
P(A and B)
0.6
If A and B are assumed to be dependent and mutually non-exclusive events,
P(A or B)=
If A and B are assumed to be dependent and mutually exclusive events,
P(A or B) -
Type here to search
12
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f7
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$4
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米
%23
Transcribed Image Text:P(A) = 0.2 P(B) = 0.4 P(B| A) = 0.24 Round solutions to three decimal places, if necessary. If A and B are assumed to be dependent events, P(A and B) = If A and B are assumed to be independent events, P(A and B) 0.6 If A and B are assumed to be dependent and mutually non-exclusive events, P(A or B)= If A and B are assumed to be dependent and mutually exclusive events, P(A or B) - Type here to search 12 f6 f7 esc ? @ $4 & 1 2 3 近 米 %23
Expert Solution
Step 1

Given that:

PA=0.2PB=0.4PB|A=0.24

 

a) If A and B are dependent events,

 PA and B=PAB=PB|A×PA=0.24×0.2=0.048

b) If A and B are independent events,

PA and B=PAB=PA×PB=0.2×0.4=0.08

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