Part: 0/2 Part 1 of 2 (a) An article in a medical journal suggested that approximately 16% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.04? A sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 using the estimate 0.16 for p. Part: 1/2 Part 2 of 2 b) Estimate the sample size needed if no estimate of p is available. sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 when no stimate of p is available. X X S

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter4: Equations Of Linear Functions
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Surgical complications: A medical researcher wants to construct a 99.9% confidence interval for the proportion of knee replacement surgeries that result in
complications.
Part: 0/2
ontinue
Part 1 of 2
(a) An article in a medical journal suggested that approximately 16% of such operations result in complications. Using this estimate, what sample size is
needed so that the confidence interval will have a margin of error of 0.04?
A sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 using the
estimate 0.16 for p.
Part: 1 / 2
Part 2 of 2
(b) Estimate the sample size needed if no estimate of p is available.
A sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 when no
estimate of p is available.
X
X
S
Ś
Transcribed Image Text:Surgical complications: A medical researcher wants to construct a 99.9% confidence interval for the proportion of knee replacement surgeries that result in complications. Part: 0/2 ontinue Part 1 of 2 (a) An article in a medical journal suggested that approximately 16% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.04? A sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 using the estimate 0.16 for p. Part: 1 / 2 Part 2 of 2 (b) Estimate the sample size needed if no estimate of p is available. A sample of operations is needed to obtain a 99.9% confidence interval with a margin of error of 0.04 when no estimate of p is available. X X S Ś
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