Part a) A plant undergoes photosynthesis in order to synthesize glucose (C6H12O6), according to the following equation: 6CO2(g) + 6H2O(l) + sunlight → C6H12O6(s) + 6O2(g) One day, a plant took in 0.0480 mol of CO2 and had excess watering and sunlight. It produced 1.10 g of glucose. What is the percentage yield of glucose? Part b) How would a cloudy day affect the percentage yield of the reaction (i.e. would it increase or decrease)? Explain.
Part a) A plant undergoes photosynthesis in order to synthesize glucose (C6H12O6), according to the following equation: 6CO2(g) + 6H2O(l) + sunlight → C6H12O6(s) + 6O2(g) One day, a plant took in 0.0480 mol of CO2 and had excess watering and sunlight. It produced 1.10 g of glucose. What is the percentage yield of glucose? Part b) How would a cloudy day affect the percentage yield of the reaction (i.e. would it increase or decrease)? Explain.
Chapter3: Stoichiometry
Section: Chapter Questions
Problem 145AE: A potential fuel for rockets is a combination of B5H9 and 0 2. The two react according to the...
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Part a) A plant undergoes photosynthesis in order to synthesize glucose (C6H12O6), according to the following equation:
6CO2(g) + 6H2O(l) + sunlight → C6H12O6(s) + 6O2(g)
One day, a plant took in 0.0480 mol of CO2 and had excess watering and sunlight. It produced 1.10 g of glucose. What is the percentage yield of glucose?
Part b) How would a cloudy day affect the percentage yield of the reaction (i.e. would it increase or decrease)? Explain.
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