Part A (Figure 1) shows a meter stick held lengthwise along the optical axis of a converging mirror. How long is the image of the meter stick? Assume that d = 57 cm. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Express your answer with the appropriate units. ? L' = Value cm Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Figure 1 of 1 Provide Feedback f= 40 cm Meter stick 100 cm d

Part A (Figure 1) shows a meter stick held lengthwise along the optical axis of a converging mirror. How long is the image of the meter stick? Assume that d = 57 cm. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Express your answer with the appropriate units. ? L' = Value cm Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Figure 1 of 1 Provide Feedback f= 40 cm Meter stick 100 cm d

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter37: Reflection And Images Formed By Reflection

Section: Chapter Questions

Problem 64PQ

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part e) Which statement best describes the image that is formed? The image is real because the reflected principal rays may be extrapolated to converge at a common point. The image is virtual because the reflected principal rays physically converge at a common point. The image is virtual because the reflected principal rays may be extrapolated to converge at a common point. The image is real because the reflected principal rays physically converge at a common point.
Suppose you have a concave mirror as shown in the image below. If h = 1.84m is the height of an object (really the displacement of the top of the object from the axis) and h′ = 4.21m is the height of the image, what is the magnitude of the transverse magnification (in units of meters)?
Part A: State the characteristics of the image formed by a converging lens when the object is distance is less than the focal length of the lens. An object (2.0 mm high) is place at a distance of 30 cm in front of a diverging lens of focal length 20 cm. Calculate the image distance of the image produced by the lens and verify all the characteristics listed in question (2).
A student is getting her picture taken by a digital camera. The student is ho = 1.95 m tall and she stands d0 = 3.25 m in front of the camera lens which has a focal length of f = 0.026 m. ho = 1.95 md0 = 3.25 mf = 0.026 m Part (a) Input an expression for the resulting image distance, di. di =? Part (b) By evaluating the numerical distance, find out if the image is real or virtual. Part (c) Numerically, what is the magnification of the system? m =? Part (d) Numerically, what is the image height in meters? hi =?
An object is placed at a distance of 1.33 metres from a convex lens that has a focal length of 40 millimetres.a) Where would you look (distance and apparent location from the lens) for a focused image to appear?b) What orientation would the image appear: right-side-up or upside-down?c) Determine the magnification of the image. Does your value confirm the answer in part b)?10d) If the object’s distance from the lens was shortened to 1.33 centimetres, how would the focused image change, including the magnification?
Draw a ray-tracing diagram for an object located 3f away from a concave mirror with focal length f. Is the image real or virtual? Upright or inverted? Justify your answers. Describe the magnitude and sign of the lateral magnification m.
: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.26 Part a: What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? Part b: what is the focal length of the mirror in meters ? Part c: what is it radius of curvature in meters?
Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 7.5 cm (left lens) and 35 cm (right lens) are separated by a distance 25 cm. If a 2.9 cm tall object is placed as indicated in part (a), and the image formed is 0.74 cm tall, what is the magnification of the first lens? M1 =
All problems involve a concave (converging) mirror that has a radius of curvature of 18.0 m.For problems 1-4, an object of height 12.0 cm is placed 15.00 m in front of the mirror. Calculate the image distance, the image height, and the magnification(not necessarily in that order). 1) Calculate di. 2) Calculate hi. 3) Calculate the magnification m. 4) Where is the image formed? A) on the object side of the optic B) on the side of the optic opposite the object C) there is no image formed
PLEASE ANSWER D, E, AND F An object is placed 11.0 cm in front of a concave mirror with radius of curvature of 30.0 cm. a. What is the focal length of the mirror? ________________________ b. What is the image distance? ________________________ c. What is the magnification? ________________________ d. Is the image (circle the answer): real or virtual? upright or inverted? enlarged or reduced in size? e. Draw a ray diagram. f. If a different object, 10.0 cm tall, is placed in front of the mirror and the image appears inverted and 2.00 cm tall, how far from the mirror was that object placed? ___________________
1) A room in a "hall of mirrors" has two flat mirrors on opposite walls, so that a person standing between the mirrors sees a "never-ending" series of reflections. A person stands 1.90 m from the mirror on the left wall and 5.40 m from the mirror on the right wall. What are the distances (in m), as measured from the person, for the first three images seen by the person in the left wall mirror? first image m second image m third image m A triangular glass prism with apex angle of Φ = 60.0° has an index of refraction n = 1.58 (see figure below). What is the smallest angle of incidence ?1 for which a light ray can emerge from the other side?
Part A: In the above figure, a light beam shines through air and then strikes a mirror, making an angle theta = 23.2 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.32 cm, located a distance y= 57.6 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? Part B: This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 37.5 degrees, y = 27.1 cm and h = 1.34 cm. What is x now? PLEASE ANSWER BOTH PARTS.