Part A If a car is moving to the left with constant velocity, one can conclude that ANSWER: there must be no forces exerted on the car. the net force exerted on the car is directed to the left. the net force exerted on the car is zero. there is exactly one force exerted on the car. Part B An object cannot remain at rest unless ANSWER: there are no forces at all exerted on it. the net force exerted on it is zero. the net force exerted on it is constant. there is only one force exerted on it.

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter5: Newton's Law Of Motion
Section: Chapter Questions
Problem 57P: Two teams of nine members each engage in tug-of-war. Each of the first team’s members has an average...
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Part A
If a car is moving to the left with constant velocity, one can conclude that
ANSWER:
there must be no forces exerted on the car.
the net force exerted on the car is directed to the left.
the net force exerted on the car is zero.
there is exactly one force exerted on the car.
Part B
An object cannot remain at rest unless
ANSWER:
there are no forces at all exerted on it.
the net force exerted on it is zero.
the net force exerted on it is constant.
there is only one force exerted on it.
Transcribed Image Text:Part A If a car is moving to the left with constant velocity, one can conclude that ANSWER: there must be no forces exerted on the car. the net force exerted on the car is directed to the left. the net force exerted on the car is zero. there is exactly one force exerted on the car. Part B An object cannot remain at rest unless ANSWER: there are no forces at all exerted on it. the net force exerted on it is zero. the net force exerted on it is constant. there is only one force exerted on it.
A crate with mass 33.0 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 12.0 N.
Part A
What is the magnitude of acceleration?
Express your answer in meters per second squared.
ANSWER:
a =
m/s?
Part B
How far does the crate travel in 12.0 s?
Express your answer in meters.
ANSWER:
m
Part C
What is its speed at the end of 12.0 s?
Express your answer in meters per second.
ANSWER:
V =
m/s
A Space Walk
Transcribed Image Text:A crate with mass 33.0 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 12.0 N. Part A What is the magnitude of acceleration? Express your answer in meters per second squared. ANSWER: a = m/s? Part B How far does the crate travel in 12.0 s? Express your answer in meters. ANSWER: m Part C What is its speed at the end of 12.0 s? Express your answer in meters per second. ANSWER: V = m/s A Space Walk
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