Calculate the molar mass for Mn3O7, an oxide of manganese. Express your answer to five significant figures. > View Available Hint(s) ΑΣφ ? Molar mass Submit Part C Calculate the molar mass of acetylcholine ( C,NH16O2), a neurotransmitter that activates muscles.
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- Vanadic ion, V3+, forms green salts and is a good reducingagent, being itself changed in neutral solutions to thenearly colorless ion V(OH)4+. Suppose that 15.0 mL of a0.200-M solution of vanadic sulfate, V2(SO4)3, was neededto reduce completely a 0.540-g sample of an unknownsubstance X. If each molecule of X accepted just oneelectron, what is the molecular weight of X? Suppose thateach molecule of X accepted three electrons; what wouldbe the molecular weight of X then?Give typed full explanation A stock solution of lithium phosphate (Li3PO4, MM= 115.794361 g/mol) is prepared by dissolving 295.8 g Li3PO4 in deionized water to a final total volume of 1.000 L. Suppose a 1.000-mL aliquot is taken from this stock solution and transferred to a new container to which deionized water is added until the total volume is 50.00 mL. A new 1.000-mL aliquot is taken from this 50.00 mL solution and transferred to a third container to which deionized water is added until the total volume is 25.00 mL. Calculate the number of individual lithium ions (Li+) in the final 25.00-mL solution. Note that lithium phosphate is a strong electrolyte that completely dissociates in water (note that (aq) means the species is a solute in an aqueous solution): Li3PO4 (aq) 3 Li+ (aq) + PO43– (aq) Report your answer to two significant figures. Use scientific notation. Example: 1.0*10^23 (this notation means 1.0 1023)1. What are the important considerations in determining the % ash content and elemental contents of plants under investigation? 2. Suggest other methods of analysis of commercial herbal drugs. Enumerate and discuss each.
- What volume of 0.200 M NaOH is necessary to neutralize the solution produced by dissolving 2.00 g of PCl3 is an excess of water? Note that when H3PO3 is titrated under these conditions, only one proton of the acid molecule reacts.1. Discuss the following roles in the liquid-liquid extraction of dyes. a. Vinegar b. Baking soda1A. What weight (in grams) of oxalic acid (MW= 90 g/mol) will be required to prepare 1 liter of 0.25 N? 1b. What weight in milligrams of potassium iodate would liberate sufficient iodine to consume 25.9mL of 0.1N sodium thiosulfate? Mw potassium iodate is 214 g/mol
- Given: 0.35g NaCl, 0.25 g NaHCO3, 0.15 g KCl & 2 g C6H12O6 are present in 100 mL ORS solution (MW: Na: 23, K: 39, Cl: 35, H: 1, C: 12, O: 16) Calculate the total amount of bicarbonate expressed in mmol/L present in the prepared solution a 90.10 mmol/L b 80.61 mmol/L c 29.76 mmol/L d 60.34 mmol/L e 111.11 mmol/L f 20.27 mmol/LA student determined the chloride content of a commercial salt by using the Mohr method. A 0.7725 -g sample of the salt was dissolved in distilled water and diluted to a final volume of 250. mL. A 25.-mL aliquot of the analyte solution was then titrated against a standard 0.0347 M AgNO3(aq) solution to the chromate end-point. A blank-corrected volume of 25.96 mL was recorded. Calculate the percent chloride in the sample.A student determined the chloride content of a commercial salt by using the Mohr method. A 0.7725 -g sample of the salt was dissolved in distilled water and diluted to a final volume of 250. mL. A 25.-mL aliquot of the analyte solution was then titrated against a standard 0.0347 M AgNO3(aq) solution to the chromate end-point. A blank-corrected volume of 25.96 mL was recorded. Calculate the percent chloride in the sample. Provide your answer to two decimal places and without units.
- Given: 0.35g NaCl, 0.25 g NaHCO3, 0.15 g KCl & 2 g C6H12O6 are present in 100 mL ORS solution (MW: Na: 23, K: 39, Cl: 35, H: 1, C: 12, O: 16) Calculate the total amount of chloride expressed in mmol/L present in the prepared solution 60.34 mmol/L 90.10 mmol/L a 111.11 mmol/L b 29.76 mmol/L c 80.61 mmol/L d 20.27 mmol/LComplete and balance the following:(a) As(s) +excess O₂(g)→ (b) Bi(s) excess +F₂(g) →(c) Ca₃As₂(s)+ H₂O(l)→9bii and 11b