Part b.) A hiker starts walking due west from Sasquatch Point and gets to the Chupacabra Trailhead before she realizes that she hasn't reset her pedometer. From the Chupacabra Trailhead, she hikes for 5 miles along a bearing of N53°W which brings her to the Muffin Observatory. From there, she knows that a bearing of S65°E will take her straight back to Sasquatch Point. How far will she have to walk to get from the Muffin Ridge Observatory to Sasquatch Point? (Round your answer to 2 decimal places)  _____ mi  What is the distance between Sasquatch Point and the Chupacabra Trailhead? (Round your answer to two decimal places)  _____ mi    (Can you please explain in steps how you solved these problems?)

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter1: Introduction And Vectors
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Problem 7CQ
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Part b.) A hiker starts walking due west from Sasquatch Point and gets to the Chupacabra Trailhead before she realizes that she hasn't reset her pedometer. From the Chupacabra Trailhead, she hikes for 5 miles along a bearing of N53°W which brings her to the Muffin Observatory. From there, she knows that a bearing of S65°E will take her straight back to Sasquatch Point. How far will she have to walk to get from the Muffin Ridge Observatory to Sasquatch Point? (Round your answer to 2 decimal places) 

_____ mi 

What is the distance between Sasquatch Point and the Chupacabra Trailhead? (Round your answer to two decimal places) 

_____ mi 

 

(Can you please explain in steps how you solved these problems?)

(a) Find the angle 0 in standard position with 0° ≤ 0 < 360° which corresponds to each of the bearings given below.
(i) due west
(ii) S83°E
(iii) N6.5°E
(iv) due south
(v) N33.25°W
(vi) S70°43'14'W
(vii) N45°E
(viii) S45°W
O
O
Transcribed Image Text:(a) Find the angle 0 in standard position with 0° ≤ 0 < 360° which corresponds to each of the bearings given below. (i) due west (ii) S83°E (iii) N6.5°E (iv) due south (v) N33.25°W (vi) S70°43'14'W (vii) N45°E (viii) S45°W O O
In this series of exercises we introduce and work with the navigation tool known as bearings. Simply put, a bearing is the direction you are heading according to a
compass. The classic nomenclature for bearings, however, is not given as an angle in standard position, so we must first understand the notation. A bearing is
given as an acute angle of rotation (to the east or to the west) away from the north-south (up and down) line of a compass rose. For example, N40°E (read "40°
east of north") is a bearing which is rotated clockwise 40° from due north. If we imagine standing at the origin in the Cartesian Plane, this bearing would have us
heading into Quadrant I along the terminal side of 0 = 50°. Similarly, S15°W would point into Quadrant III along the terminal side of 0 = 255° because we started
out pointing due south (along = 270°) and rotated clockwise 15° back to 255°. Counter-clockwise rotations would be found in the bearings N60°W (which is on
the terminal side of 0 = 150°) and S27°E (which lies along the terminal side of 0 = 297°). These four bearings are drawn in the plane below.
-
The cardinal directions north, south, east and west are usually not given as bearings in the fashion described above, but rather, one just refers to them as 'due
north', 'due south', 'due east' and 'due west', respectively, and it is assumed that you know which quadrantal angle goes with each cardinal direction. (Hint: Look
at the diagram below.)
N60°W
W
60°
$15°W
Z
15%
40°
27°
N40°E
S27°E
>Ε
Transcribed Image Text:In this series of exercises we introduce and work with the navigation tool known as bearings. Simply put, a bearing is the direction you are heading according to a compass. The classic nomenclature for bearings, however, is not given as an angle in standard position, so we must first understand the notation. A bearing is given as an acute angle of rotation (to the east or to the west) away from the north-south (up and down) line of a compass rose. For example, N40°E (read "40° east of north") is a bearing which is rotated clockwise 40° from due north. If we imagine standing at the origin in the Cartesian Plane, this bearing would have us heading into Quadrant I along the terminal side of 0 = 50°. Similarly, S15°W would point into Quadrant III along the terminal side of 0 = 255° because we started out pointing due south (along = 270°) and rotated clockwise 15° back to 255°. Counter-clockwise rotations would be found in the bearings N60°W (which is on the terminal side of 0 = 150°) and S27°E (which lies along the terminal side of 0 = 297°). These four bearings are drawn in the plane below. - The cardinal directions north, south, east and west are usually not given as bearings in the fashion described above, but rather, one just refers to them as 'due north', 'due south', 'due east' and 'due west', respectively, and it is assumed that you know which quadrantal angle goes with each cardinal direction. (Hint: Look at the diagram below.) N60°W W 60° $15°W Z 15% 40° 27° N40°E S27°E >Ε
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