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- Implement the following cpp program in MIPS, upload the MIPS source code and the screenshot of program execution results int multiply(int x, int y){int product=0;if(x>y)for(int i=0;i<y;i++)product+=x;if(y>x)for(int i=0;i<x;i++)product+=y;return product;}Consider a telegraph source having two symbols, dot and dash. The dot duration is 0.2 second. The dash duration is three times the dot duration. The probability of the dot’s occurring is twice that of the dash, and the time between symbols is 0.2 second. Assume n = 2 ( 2nd extension of the code), pdash = S0 and pdot = S11. Determine the equivalent codeword for each symbol using Shannon Code. Supersymbol Code S0 S0 S0 S1 S1 S0 S1 S1 2. Determine the coding efficiency.A circuit has four inputs p,q,r,s representing the natural binary number 0000=0,to 1111=15 p is the most significant bit .the circuit has one output, x,which is true if the input to the circuit represent is a prime number and false other wise (A) design a true table for this circuit, and hence obtain an expression for x in terms of P,Q,R,S.
- Express the following in canonical forms , simplify using KMAP and make a truth table of the simplified expression: 1. F(x, y, z) = π (0, 2, 5, 7) 2. F(A, B, C, D) = ∑ (0, 1,2,5,8,9, 10) 3. F(w, x, y, z) = Σ (I, 3, 7,11,15) + d(w, x, y, z) = Σ (0, 2, 5) 4. F(A, B, C, D, E) = Σ(0, 1,4,5,16,17,21,25,29) Note: Pls. show groupings and highlight if possible.Simplify the following Boolean function and expression, using four-variable maps a) cF(w,x,y,z) = Σ (2,3,10,11,12,13,14,15) b) dF = x’z + w’xy’ + w(x’y + xy’) c) eF = A’B’C’D’+AC’D’+B’CD’+A’BCD+BC’DWhat is F in SOP in expression F(w,x ,y z) = Σ(2, 4, 6, 8, 10, 12): d(0, 1, 3, 5, 7, 9, 11, 13, 14, 15) a. 1 b. F = (wx) + (yz) c. F = (xyz) + (wz) + (yz) d. F = (wy) + (xz)
- Using a 6-bit cell to store integers in 2's complement, NEG 1 1 0 1 0 0 = ______ ? A. 0 0 1 0 1 1 ' B. 0 1 0 1 0 0 C. 1 0 1 0 1 1 D. 0 0 1 1 0 0 E. 1 1 1 0 0 1 Which of following gives the correct canonical sum of products for X A. X = AB + AB' + A'B + A'B' B. X = A'B' + A'B + AB' C. X = (A+B)(A+B')(A'+B)(A'+B') D. X = (A'+B')(A'+B)(A+B')(A+B) None of aboveGiven five inputs (a, b, c, d, e) connected to 8051’s port P1 and P2 with : P1.0 = a, P2.0 = b, P1.3 = c, P2.7 = d et P1.6 = e. Outputs S0 and S1 are connected to P3.0 and P3.1 respectively as shown in the figure below. We propose to realize the following logic S0 = a.b + c.d + e.(a.b + a.b) S1 = c.b + d + e.a.b90. In CRC checksum method, assume that given frame for transmission is 1101011011 and the generator polynomial is G(x) = x^4 + x + 1.After implementing CRC encoder, the encoded word sent from sender side is ............. a. 11010110111110 b. 11101101011011 c. 110101111100111 d. 110101111001111
- A 1-bit output Y pattern recognizer accepts a 1-bit input X. Only if the 1-0-1 pattern is observed at X does Y become 1. The incoming bit stream is treated by the circuit as overlapping sequences, with the last bit of one sequence becoming the first bit of the next. In action, the circuit compares the most recent three bits to the pattern, as shown below. X 0 0 1 0 1 0 1 1 1 0 1 0 0 1 0 1 0 1 1 Y 0 0 0 0 1 0 1 0 0 0 1 0 0 0 0 1 0 1 0 Clearly shows the STATE DIAGRAM, STATE ASSIGNMENT INDICATING WHICH BINARY PATTERN CORRESPONDS TO WHICH STATE, EXCITATION TABLE, K-MAPS AND EQUATIONS AND ITS CORRESPONDING CIRCUIT.A DMS has a maximum entropy Hmax = 3.321. If it makes a message in which symbol si is repeated i times, i = 1, 2, …. Find the information of the fourth and last symbols in the message.A Sequence Detector is a circuit which given an input string of bits generates an output 1 whenever the target sequence (pattern) has been detected. There are two types of sequence detectors: Overlapping: The detector allows overlapping, hence the final bits of one sequence can be the start of another sequence. Non-overlapping: The detector does not allow overlapping, hence a new sequence starts only after the previous sequence is completed. Ex: Detect pattern 101 For non-overlapping case: Input :0110101011001 Output:0000100010000 For overlapping case: Input :0110101011001 Output:0000101010000 Design a sequential circuit (overlapping) with an input ‘x’. The pattern to be detected is the binary number that is equal to 1001100 For example,the circuit detects the sequence 00010 . When the sequence is detected, the detector outputs z=‘1’ For this circuit: Draw the ASM diagram. Construct the state table. Draw the logic circuit for the datapath and control in logisim.