Part ii alone please The condensation reaction of acetone (CH3)2CO în aqueous solution is catalysed by base B, which (b) reacts reversibly with acetone to form the carbion, C3H50¯. The carbion then reacts with a molecule of acetone to give product P k АН BH A A НА k2 AH = acetone A = carbion B = base catalyst (i) Use steady state approximation to determine the concentration of the carbion and hence derive the rate equation for the formation of product, P. (ii) Given the rate law derived in part (b) (i), show how at high initial concentration of acetone, that the derived rate law becomes 2nd order and how also it can be expressed under certain conditions as a pseudo first order rate law. Secondly show from pseudo first order rate equation how kị can be determined from a plot of '/k! 1 versus 1/ [B]o.

Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter21: Rates Of Chemical Reactions, Ii. A Clock Reaction
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Part ii alone please
The condensation reaction of acetone (CH3)2CO în aqueous solution is catalysed by base B, which
(b)
reacts reversibly with acetone to form the carbion, C3H50¯. The carbion then reacts with a molecule of
acetone to give product P
k
АН
BH
A
k.1
A
НА
k2
AH = acetone A = carbion B = base catalyst
(i)
Use steady state approximation to determine the concentration of the carbion and hence
derive the rate equation for the formation of product, P.
(ii)
Given the rate law derived in part (b) (i), show how at high initial concentration of acetone,
that the derived rate law becomes 2nd order and how also it can be expressed under certain
conditions as a pseudo first order rate law. Secondly show from pseudo first order rate
equation how kị can be determined from a plot of /k!
1
versus 1/ [B]o.
Transcribed Image Text:Part ii alone please The condensation reaction of acetone (CH3)2CO în aqueous solution is catalysed by base B, which (b) reacts reversibly with acetone to form the carbion, C3H50¯. The carbion then reacts with a molecule of acetone to give product P k АН BH A k.1 A НА k2 AH = acetone A = carbion B = base catalyst (i) Use steady state approximation to determine the concentration of the carbion and hence derive the rate equation for the formation of product, P. (ii) Given the rate law derived in part (b) (i), show how at high initial concentration of acetone, that the derived rate law becomes 2nd order and how also it can be expressed under certain conditions as a pseudo first order rate law. Secondly show from pseudo first order rate equation how kị can be determined from a plot of /k! 1 versus 1/ [B]o.
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