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Oogenesis
The formation of the ovum (mature female gamete) from undifferentiated germ cells is called oogenesis. This process takes place in the ovaries (female gonads). Oogenesis consists of three stages known as the multiplication phase, growth phase, and maturation phase.
Cell Division
Cell division involves the formation of new daughter cells from the parent cells. It is a part of the cell cycle that takes place in both prokaryotic and eukaryotic organisms. Cell division is required for three main reasons:
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- The statement is true or false "A person having XO karyotype is genotypically a male"?TrueFalseGilbert's genetic makeup is homozygous for dark hair. Jan's is homozygous for blond hair. What proportion of their children are likely to be dark-haired? Explain.A single allele gives rise to the HbS form of hemoglobin. Individuals who are homozygous for the allele HbS/HbS develop sickle-cell anemia Section 9.5. Heterozygous individuals HbA/ HbS have few Symptoms. A couple who are both heterozygous for the HbS allele plan to have children. For each of the pregnancies, determine the probability that their child will be: a. homozygous for the HbS allele b. homozygous for the normal allele HbA c. heterozygous: HbA/HbS
- Analysis of Autosomal Recessive and Dominant Traits Huntington disease is a rare, fatal disease that usually develops in the fourth or fifth decade of life. It is caused by a single autosomal dominant allele. A phenotypically normal man in his twenties who has a 2-year-old son of his own learns that his father has developed Huntington disease. What is the probability that he himself will develop the disease? What is the chance that his young son will eventually develop the disease?n humans, Turner's syndrome results in a ["Female", "Male", "Hermaphrodite"] with the sexual genotype X0. Klinefelter's syndrome results in a ["Y0", "Male", "XY", "X0", "Female", "XXX", "XXY", "XX", "Hermaphrodite"] with the sexual genotype XXY. (No partial credit given)Suppose that a heterozygous female mates with a heterozygous male. What is the probability that a child produced from this union will develop Parkinson disease-14?please show punnett square also
- Shown above is a family pedigree tree in which family members afflictedwith the disease Haemophilia are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passingon the disease to their future children (represented by the ? symbolabove) because the hemophilia runs in the woman’s family. Turner syndrome is a disease in which an individual is bornwith only a single X chromosome. Suppose the woman in thecouple is a carrier for hemophilia and has a child with Turnersyndrome. Would this child have the disease?Suppose that a female with the mutation (i.e., a heterozygous female) mates with a healthy male (the male’s genotype is homozygous recessive). What is the probability that their child has an increased susceptibility to breast cancer?please show punnett square alsoFor each genotype, indicate whether it is homozygous (hom) or heterozygous (het). ________ Zz ________ bb ________ MM ________ Tt ________ cc ________ AA
- Marly is doing a paternity test to determine who could be her father. She is going just off of word of mouth for now so there is no way for her to figure out the genotypes of ther potential fathers. She knows for certain that she is type A with the genotype (A^I A^i). Her potential fathers are Gayle who is a Type O, Jake who is type A,and Mark who is Type AB. Who could be the potential father?Label if genotype is RR (homozygous) or Rr (heterozygous) No freckles (f) Straight widow's peak (w) Free hanging ear lobe (A) No cleft chin (c) Hitchhiker's thumb (H) No Dimples (d) Interlocking Fingers (Right thumb on top) (l)A women is heterozygous, Aa, for classic albinism and this gene maps to chromosome 11, and is a carrier for haemophilia, an X-linked trait (H/h). Provide a diagram of chromosomes 11 and the sexchromosomes (show the alleles associated with albinism and haemophilia) in the cells involved with normal oogenesis for this female. Start with the oogonium and end with the mature ovum; you can ignore all polar bodies. Your diagrams should show the chromatids clearly and all cells must be labelled. Indicatethe total number of chromosomes and chromatids for each cell stage.