ir spectrum, identify the compound %Transmittance3345.22*3026.172863.691665.761493.748.84OE'OLEL1202.891008.08S919.23965.16690.460608AconeF0930-0007Wavenumbers (cm-1)0001009000000E009EFIND PEAKS:Spectrum:Region:Absolute threshold: 100.204Sensitivity:Peak list00'00000'0034 413 IHD - 2at2Position:Position:Position:Position:Position:Position:Position:Position:690,46733.29833.07919.23965.161008.081068.991091.62Intensity:Intensity:Intensity:Intensity:Intensity:Intensity:Intensity:Intensity:50,54389.4832.46.86568.63574,24372.221

IR peak corresponds to different functional groups present in a molecule.

Answered: %Transmitance 3345.22 1665.76…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter24: Introduction To Spectrochemical Methods

Section: Chapter Questions

Problem 24.2QAP

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Use the data in Figure 4.8 to estimate the ratio of radiation intensity at 10,000 Å (infrared) to that at 5000 Å (visible) from a blackbody at 5000 K. How will this ratio change with increasing temperature? Explain how this change occurs.
An absorption measurement with a 1 cm path length yields a reading of 0.004 absorbance units with a noise of 0.001 absorbance units and a mean noise reading of 0 for 10 scans averaged together. Assuming the noise for a single scan does not change if the path length is increased to 6 cm and the number of scans is increase to 100, what is the signal to noise of the new measurement.
A 1.2cm diameter glass cuvette is filled with a Cu(NH3)42+ solution that is deep blue. The cuvette is placed into a pre-blanked spectrophotometer. At 620nm, the transmittance is 23%. If the solution has molarity = 0.0133 M and path length of light through the solution = 1.2 cm, what is the value of molar absorptivity at 620 nm?
A solution of KMnO4 with a concentration of 8.25 x 10-5 M yields an absorbance value of 0.1302 when measured in a 5.60 cm cuvette, set at a wavelength of 725 nm. Compute for the Molar Absorptivity Coefficient of the sample. Choices: a. 2.8182x10-8 c. 4.8182x10-8 b. 3.8182x10-8 d. 5.8182x10-8
The molar absorptivity for aqueous solutions of phenol at 211 nm is 6.17 × 103 L cm-1 mol-1. Calculate the permissible range of phenol concentrations if the transmittance is to be less than 85% and greater than 7% when the measurements are made in 1.00-cm cells.
Potassium dichromate and potassium permanganate have overlapping absorptionspectra in 1M H2SO4 . K2Cr2O7 has an absorption maxima at 440 nm, and KMnO 4 has a band at 545nm (the maximum is actually at 525 nm, but the longer wavelength is generally used whereinterference from K2C2O7 is less). A mixture is analyzed by measuring the absorbance at these twowavelengths with the following results: A 440 =0.405, A 545 =0.712 in a 1-cm cell. The absorbances ofpure solutions of K2Cr2O7 (1x10 -3 M) and KMnO 4 (2.00x10 -4 M) in 1 M H 2 SO 4 , using the same cell gavethe following results: A Cr,440 = 0.374, A Cr,545 = 0.009, A Mn,440 =0.019, A Mn,545 = 0.475. Calculate theconcentrations of dichromate and permanganate in the sample solution.
Concentration [M] Absorbance Solution 1 86.29 0.64 Solution 2 51.986 0.29 …. Fig 1: [graph of the calibration curve, make sure to show: function, R2, 0 intercept]
Calculate the resolution required to resolve the following peaks; i) CH3N+ (MW = 28.0187) and N2+ (MW = 28.0061) ii) C2H4+ (MW = 28.0313) and CO+ (MW = 27.9949) iii) C3H7N3+ (MW = 85.0641) and C5H9O+ (MW = 85.0653) iv) 116Sn+ (At W = 115.90219) and 232Th2+ (At W = 232.03800)
The following are the reasons why instrumental analysis methods are used, except for: a. Narrow concentration ranges may be detected. b. Extreme low sensitivity, with molecule and noise signal detection. c. Separate equipment or facilities for control, data handling, and optimization procedures. d. All of the above
What percent transmittance range and what absorbance range are considered to be the optimum working ranges for spectrochemical measurements?
Given the following data find the Molar absorption coefficient for Fe(SCN)^2+}Fe(SCN)X2+, (M−1 cm−1), if the length is 2.24cm. FIND THE UNROUNDED VALUE. Unrounded Rounded Molar absorption coefficient for \ce{Fe(SCN)^2+}Fe(SCN)X2+, (M−1 cm−1) Sample FROM PRELAB EXPERIMENTAL DATA CALCULATED VALUES 0.000300 M Absorbance Fe(SCN)X2+]equ, (M) --> for next bar 1 1.50 0.210166 0.0000300 2 3.50 0.466178 0.0000700 3 7.00 0.912604 0.000140 4 10.00 1.348948 0.000200 SLOPE, (M−1) INTERCEPT R^2R2 Unrounded 6.66606 × 103 1.20727 × 10-3 0.998979
The transmittance of a solution in 1-cm cuvette is 60.0%. Calculate the transmittance of the same solution in 2-cm cuvette.

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%Transmitance 3345.22 1665.76 1597.577.05 1493.7248.84 1202.89 9 T001.62 1068.b08.08 965.16 019.23 ND PEAKS: Wavenumbers (cm-1) 00sz Pos fogn 00s 000L 00SL 000z 0000 00SE 000 09 -08 06 00L